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SpyIntel [72]
3 years ago
12

How many unpaired electron are there is CO2+ ion

Chemistry
1 answer:
Leviafan [203]3 years ago
3 0

3 unpaired electrons...

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calculate δg o for each reaction using δg o f values: (a) h2(g) i2(s) → 2hi(g) 2.6 kj (b) mno2(s) 2co(g) → mn(s) 2co2(g) kj (c)
Reika [66]

(a)The change in Gibbs free energy for the reaction has been 2.6 kJ/mol.

(b) The change in Gibbs free energy for the reaction has been -49.3 kJ/mol.

(c) The change in Gibbs free energy for the reaction has been 91.38 kJ/mol.

6 0
2 years ago
Given the following information:
bonufazy [111]

Answer:

Ya'll should really practice more because things like these are easy

Explanation:

6 0
3 years ago
How many atoms of hydrogen are in 0.500 mol of ch3oh molecules?
cestrela7 [59]
In 1 mol of CH3OH, you have 4 H-atoms (because 3 H-atoms are attached to the C-atom, and one H-atom in the OH group). That means in 0.500 mol of CH3OH, you have 2 H-atoms since it is halved. And then we have Avogadro's constant: 6.02 * 1023.

The question asks for how many hydrogen atoms there are in 0.500 mol CH3OH. Using the numbers that we have (Avogadro's constant and no. of H-atoms), the answer of the question will be something like:

<span>H-atoms in CH3OH = 2 * 6.02 * </span>1023<span> = ~1.2 * 10</span>24

 


8 0
3 years ago
A solution prepared by dissolving 0.100 mole of propionic acid in enough water to make 1.00 L of solution is observed to have a
torisob [31]

Answer:

C) k_a=1.3\times 10^{-5}

Explanation:

pH is defined as the negative logarithm of the concentration of hydrogen ions.

Thus,  

pH = - log [H⁺]

The expression of the pH of the calculation of weak acid is:-

pH=-log(\sqrt{k_a\times C})

Where, C is the concentration = 0.5 M

Given, pH = 2.94

Moles = 0.100 moles

Volume = 1.00 L

So, Molarity=\frac{Moles}{Volume}=\frac{0.100}{1.00}\ M=0.100\ M

C = 0.100 M

2.94=-log(\sqrt{k_a\times 0.100})

\log _{10}\left(\sqrt{k_a0.1}\right)=-2.94

\sqrt{0.1}\sqrt{k_a}=\frac{1}{10^{2.94}}

k_a=1.3\times 10^{-5}

4 0
3 years ago
Cuantos gramos de hidróxido de calcio se necesitan para preparar 875ml de solución al 2M​
PtichkaEL [24]

Answer:

129,66 g

Explanation:

Desde,

Número de moles = concentración * volumen

concentración = 2 M

volumen = 875 ml

Número de lunares = 2 * 875/1000

Número de lunares = 1,75 moles

Número de moles = masa / masa molar

masa molar de hidróxido de calcio = 74.093 g / mol

1,75 moles = masa / 74,093 g / mol

masa = 1,75 moles * 74,093 g / mol

masa = 129,66 g

7 0
3 years ago
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