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klio [65]
3 years ago
8

Why cant you ice skate on a lake when it is not frozen​

Chemistry
1 answer:
HACTEHA [7]3 years ago
4 0

Answer:

You can't ice skate on a liquid, when it is frozen it is a solid, when it's unfrozen it is a liquid

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How many atoms of hydrogen are present in 7.63 g of ammonia? please help me ??
GarryVolchara [31]
The atoms  of  hydrogen  that are  present  in  7.63 g  of ammonia(NH3)

find  the  moles  of NH3 =mass/molar mass
 7.63 g/ 17 g/mol = 0.449  moles

since there  is  3 atoms of H  in NH3 the  moles of  H = 0.449 x 3 = 1.347 moles

by  use  of  1 mole = 6.02 x10^23  atoms
what  about  1.347  moles

= 1.347  moles/1   moles  x 6.02 x10^23 atoms = 8.11 x10^23  atoms of Hydrogen
3 0
3 years ago
When energy is transferred from the air to the water, what happens to most of the energy? A. It travels through the water. B. It
BigorU [14]

Answer: Option (A) is the correct answer.

Explanation:

When energy is transferred from the air to the water then energy is absorbed by the water molecules.

This energy travels through one molecule of water to another molecule of water by the process of convection.

Thus, we can conclude that when energy is transferred from the air to the water, then it travels through the water.

3 0
3 years ago
Read 2 more answers
If you go from the Earth to the Moon, will your MASS change?
Solnce55 [7]

Answer:

No matter if you are on Earth, the moon or just chilling in space, your mass does not change. But your weight depends on the gravity force; you would weigh less on the moon than on Earth, and in space you would weigh almost nothing at all.

8 0
3 years ago
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Determine the empirical formula of an oxide of silicon from the following: mass of crucible= 18.20g, mass of crucible +silicon =
lyudmila [28]
The required empirical formula of the silicon oxide is SiO2.
4 0
3 years ago
The combustion of hydrogen-oxygen mixtures is used to produce very high temperatures (ca. 2500 °C) needed for certain types of w
tangare [24]

Answer:

1360kJ are evolved

Explanation:

When 1mole of H2 reacts with 1/2 moles O2 producing 1 mole of water and 241.8kJ.

To solve this question we need to find the limiting reactant knowing were added 90g of H2 and 90g of O2 as follows:

<em>Moles H2 -Molar mass: 2g/mol-</em>

90g H2 * (1mol / 2g) = 45 moles

<em>Moles O2 -Molar mass: 32g/mol-</em>

90g * (1mol / 32g) = 2.81moles

For a complete reaction of 2.81 moles of O2 are needed:

2.81 moles O2 * (1mol H2 / 1/2 mol O2) = 5.62 moles H2

As there are 45 moles, H2 is the excess reactant and O2 the limiting reactant.

As 1/2 moles O2 produce 241.8kJ, 2.81 moles will produce:

2.81 moles O2 * (241.8kJ / 1/2moles O2) =

<h3>1360kJ are evolved</h3>
6 0
3 years ago
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