Answer:
36 feet.
Step-by-step explanation:
We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is . We are asked to find the maximum height of the ball.
We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.
To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.
Let us find x-coordinate of parabola using formula .
So, the x-coordinate of the parabola is . Now, we will substitute in our given equation to find y-coordinate of parabola.
Therefore, the maximum height of the ball is 36 feet.
Answer:
hour= 1.25
MINUTES ANSWER= 75 minutes
Step-by-step explanation:
hope that helps>3
Answer:
(-3, 3√3)
Step-by-step explanation:
Evaluate each of the coordinates. Keep or drop the "i" as your convention requires.
6(cos(120°), i·sin(120°)) = (6·cos(120°), i·6·sin(120°)) = (6(-0.5), i·6·√3/2)
= (-3, 3√3 i)
You may want the (x, y) coordinates written as (-3, 3√3).
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In the complex plane, this is -3+i·3√3.
Answer:
y=1/2x
Step-by-step explanation: