Answer:
Option B. Sodium and potassium lose electrons and chlorine gains them
Explanation:
Sodium and Potassium are both group 1 element. They both react with chlorine by losing 1 electron each and the chlorine atom accept the electron.
Sodium chloride(NaCl) can be formed by the equation below:
Na —> Na+ + e-
Cl + e- —> Cl-
Combining both equation together we obtained the following:
Na + Cl + e- —> Na+ + Cl- + e-
Eliminating the e-, we have:
Na + Cl —> Na+Cl-
From the above illustration, we can see that sodium loses electron and chlorine accepts/gain the electron
This is also applicable to potassium chloride as shown below:
K —> K+ + e-
Cl + e- —> Cl-
Combining both equation together we obtained the following:
K + Cl + e- —> K+ + Cl- + e-
Eliminating the e-, we have:
K + Cl —> K+Cl-
we can see also that potassium loses electron and chlorine accepts/gain the electron
Therefore, the correct answer to the question is option B
Volumetric flask is the most accurate because making solutions often requires very exact volumes. Graduated cylinders are next most accurate because they can be nade thin and thus very precise. Beakers are least accurate because they are thick and extremely accurate measurements are not usually needed in beakers so manufacturers are generally less precise.
Answer:
- What is the limiting reactant?: HCl is the limitng reactant.
- How many moles of H₂ are formed?: 6.5 moles of H₂ are formed.
Explanation:
Part A: <em>what is the limiting reactant?</em>
1) <u>Balanced chemical equation</u>: given
- 2Al + 6HCl → 2AlCl₃ + 3H₂
2)<em> </em><u>Stoichiometric mole ratio:</u>
Use the coefficients of the balanced equation:
- 2 mol Al : 6 mol HCl : 2 mol AlCl₃ : 3H₂
3) <u>Compare the stoichiometric mole ratio of the reactants with their actual ratio</u>:
- Theoretical ratio: 2 mol Al / 6 mol HCl ≈ 0.33 mol Al / mol HCl
- Actual ratio: 6.0 mol Al / 13 mol Cl ≈ 0.46 mol Al / mol Cl
Since the actual ratio indicates that there is a greater number of moles of Al (0.46) per mol of Cl than what is required by the stoichiometric ratio(0.33), Al is in excess and HCl is the limiting reactant.
Answer: the limiting reactant is HCl.
Part B. <em>How many moles of H₂ are formed?</em>
3. <u>Determine how many moles of H₂ can be formed</u>
- Theoretical ratio using limiting reactant:
6 mol HCl / 3 mol H₂ = 13 mol HCl / x
⇒ x = 13 mol HCl × 3 mol H₂ / 6 mol HCl = 6.5 mol H₂.
The answer must be reported with two significant digits, such as the data are given.
Answer: 6.5 moles of H₂ are formed
Explanation:
a brittle, High melting solid : option B (MgCl2).
1) H2S
2) H2O
3) I2
weakest to strongest.
hope this helps you.