Ask question

Ask question

All categories

3 years ago

8

Which of the following represents a compound? A) H B) H-3 C)H2O D) O-16

2 answers:

LuckyWell [14K]3 years ago

7 0

The answer is C. H2

To be considered as a compound, it need to contain two on more elements.
From the option above, only H2O contains 2 elements, H is for Hydrogen and O is for oxygen. This compound formed a substance that we most commonly know as water.

adelina 88 [10]3 years ago

3 0

C, H2O represents the compound responsible for constituting water.

You might be interested in

What are particles that are close together and locked in place??

Grace [21]

Particles that are close together and locked in a place means its
a solid

3 0

2 years ago

Using the equation 2H2+O2=2H2O, when 47g of water are produced, how many grams of hydrogen must react?

Fed [463]

See , from the equation we can see that for forming two mole of H2O 2Mole of H2 has to react.

Mass of 2 Mole H2O is 18*2gm or 36gm.

So for forming 36 gm H2O 2×2 I.e. 4 gm H2 has to take part in reaction.

Therefore, to form 1 gm H2O 4÷36 gm of H2 has to take part.

So, for forming 47gm H2O (4÷36)×47 gm H2 has to take part

I.e. 5.22 gm of H2 has to take part

So, ans is 5.22 gm of hydrogen.

Hope it helps!!!

6 0

2 years ago

Read 2 more answers

Are inner planets rockier or more like gas??

Eduardwww [97]

Inner planets are rockier and outer planets are gaseous. Hope this helps! Can I have brainliest please

4 0

3 years ago

Read 2 more answers

the volume of liquid can be measured with? A. graduated cylinder B. pan balance C. scale D. metric ruler

alina1380 [7]

a: is the correct anwser

6 0

2 years ago

A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0

OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2C_2O_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL$

Putting values in above equation, we get:

$2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

$0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g$

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0

2 years ago