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kakasveta [241]
3 years ago
11

Sodium chloride (NaCl) is the chemical name for table salt and potassium chloride (KCl) is a common salt substitute. Using the p

eriodic table, choose the correct statement about how these compounds form. A. Both sodium and potassium atoms gain electrons to form ions. B. Sodium and potassium lose electrons and chlorine gains them. C. Chlorine gains electrons from potassium and loses electrons to sodium. D. Chlorine gains more electrons from potassium than it does from sodium.
Chemistry
1 answer:
Lina20 [59]3 years ago
7 0

Answer:

Option B. Sodium and potassium lose electrons and chlorine gains them

Explanation:

Sodium and Potassium are both group 1 element. They both react with chlorine by losing 1 electron each and the chlorine atom accept the electron.

Sodium chloride(NaCl) can be formed by the equation below:

Na —> Na+ + e-

Cl + e- —> Cl-

Combining both equation together we obtained the following:

Na + Cl + e- —> Na+ + Cl- + e-

Eliminating the e-, we have:

Na + Cl —> Na+Cl-

From the above illustration, we can see that sodium loses electron and chlorine accepts/gain the electron

This is also applicable to potassium chloride as shown below:

K —> K+ + e-

Cl + e- —> Cl-

Combining both equation together we obtained the following:

K + Cl + e- —> K+ + Cl- + e-

Eliminating the e-, we have:

K + Cl —> K+Cl-

we can see also that potassium loses electron and chlorine accepts/gain the electron

Therefore, the correct answer to the question is option B

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Sergio039 [100]

The concentration of the hydroxide ion given that the concentration of the hydronium ion 1.0 times 10^-14 M. The reverse mathematical method used to determine the pOH can be used to get the hydroxide ion concentration from the pOH. How many hydroxide ions are there in a solution with a pOH of 5.70, for instance.

Calculate 10-5.70, or "inverse" log, on a calculator (- 5.70). It indicates that one hydroxide ion is produced by one part of the NaOH solution. Because of this, the molar concentration of hydroxide ions in the solution is the same as the molar concentration of the NaOH.

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6 0
10 months ago
3.
belka [17]

Answer:

3. Inverse 1. Direct

Explanation:

P- pressure

V - volume

T - temperature

P1*V1 / T1 = P2*V2 / T2 ...... (1)

That's the general gas law with the combined ideas of charles, boyle & lussac.

Whenever you are restricted as "constant" temperature, volume, or pressure...cancel them off of your equation.

in this case 3. is indirectly telling us to cancel the temperature (T).

so we'll be left w P1*V1 = P2*V2

now notice that any relation ship that is multiplied like the one above consists of inversely related quantities. & so we conclude that-

P & V are inversely proportional or have an inverse relationship.

similarly in 1. we'll cancel p off of the general formula (1)

to be left with V1/T1 = V2/T2

also note that quantities involved in division are directly related to each other & hence the answer.

5 0
2 years ago
Name the salt used in plastering the fractured bone​
Eddi Din [679]
Answer: Calcium Sulphate Hemihydrate

The compound of calcium which is used for plastering of fractured bones is Plaster of Paris. It is also called as Calcium Sulphate Hemihydrate.
3 0
2 years ago
Copper is an example of a(n) __________.
navik [9.2K]
The answer is D. element

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7 0
3 years ago
Read 2 more answers
Consider the following reaction: 2Mg(s)+O2(g)-->2MgO(s) delta H=-1204kJ
Pachacha [2.7K]

Answer:

a. The reaction is exothermic.

b. -87,9 kJ

c. 9,60g of Mg(s)

d. 602kJ are absorbed

Explanation:

Based on the reaction:

2Mg(s) + O₂(g) → 2MgO(s) ΔH = -1204kJ

a. The reaction is exothermic. Because ΔH<0. That means the reaction produces heat when occurs

b. 3,55g of Mg(s) are:

3,55g Mg × ( 1mol / 24,305g) = 0,146 moles of Mg(s)

As 2 moles of Mg(s) produce -1204 kJ of heat:

0,146 moles of Mg(s) × ( -1204kJ / 2mol Mg) =  <em>-87,9 kJ</em>

c. If -238 kJ of heat were transferred. The moles of Mg(s) that react must be:

-238kJ × ( 2mol Mg / -1204kJ) = 0,395 moles of Mg(s). In grams:

0,395 moles × ( 24,305g / 1mol Mg) = <em>9,60g of Mg(s)</em>

d. The reverse reaction is:

2MgO(s) → 2Mg(s) + O₂(g)  ΔH = +1204kJ

40,5g of MgO(s) are:

40,5g MgO × ( 1mol MgO / 40,3044g) = 1,00 moles of MgO(s)

As 2 moles of MgO absorbe 1204kJ of energy:

1,00 moles of MgO(s) × ( +1204 kJ / 2mol MgO) = <em>602kJ are absorbed</em>

<em></em>

I hope it helps!

7 0
3 years ago
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