Answer : The pH of the solution is, 2.67
Explanation :
The equilibrium chemical reaction is:

Initial conc. 0.450 0 0
At eqm. (0.450-x) x x
As we are given:

The expression for equilibrium constant is:

Now put all the given values in this expression, we get:


The concentration of
= x = 0.00212 M
Now we have to calculate the pH of solution.
![pH=-\log [H^+]](https://tex.z-dn.net/?f=pH%3D-%5Clog%20%5BH%5E%2B%5D)


Therefore, the pH of the solution is, 2.67
Answer:
The molarity of the solution is 1.1 
Explanation:
Molarity is a measure of the concentration of that substance that is defined as the number of moles of solute divided by the volume of the solution.
The molarity of a solution is calculated by dividing the moles of the solute by the volume of the solution:

Molarity is expressed in units 
In this case
- number of moles of solute= 0.564 moles
- volume= 0.510 L
Replacing:

Solving:
molarity= 1.1 
<u><em>The molarity of the solution is 1.1 </em></u>
<u><em></em></u>
The closer to the top the metal is in the list, the more active the metal is and the stronger a reducing agent the metal is. When two different metals are involved in a redox reaction, the metal higher in the list will be oxidized and give up electrons that will reduce the cation of the less active metal.