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Phoenix [80]
3 years ago
14

What is the change of state involved in combustion of an alcohol and it’s entropy ?

Chemistry
1 answer:
Tanya [424]3 years ago
4 0

Answer:

idkwhat is thr qution

Explanation:

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A) Of options (a) - (d) below, highlight the (unbalanced) chemical equation that represents
labwork [276]

Answer:

c...............

Explanation:.............................yuuuuuuuuuuuuuuuuuuuuuwoopuuuuuuuu

7 0
3 years ago
36g of KOH dissolved in 800mL of water. What is the molality of the solution?
Bad White [126]

Answer:

0.80m of KOH

Explanation:

Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.

In the problem, the solute is KOH and solvent is water.

Moles of 36g KOH -Molar mass: 56.1g/mol- are:

36g KOH × (1mol / 56.1g) = <em>0.642 moles of KOH</em>

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Now, as density of water is 1g/mL, mass of 800mL of water is:

800mL × (1g / mL) × (1kg / 1000g) = <em>0.800kg of water</em>

<em></em>

Thus, molality is:

0.642moles of KOH / 0.800kg = <em>0.80m of KOH</em>

5 0
3 years ago
Calculate in witch material - sodium or zinc sulphide is the highest percentage by mass of sulfur ​
rjkz [21]

Answer:

sodium sulphide.

Explanation:

First, let us obtain the percentage of sulphur in both compounds. This is illustrated below:

For sodium sulphide(Na₂S):

Molar Mass of Na₂S = (23x2) + 32 = 46 + 32 = 78g/mol

Percentage of sulphur in Na₂S is given by:

32/78 x 100 = 41%

For zinc sulphide(ZnS):

Molar Mass of ZnS = 65.4 + 32 = 97.4g/mol

Percentage of sulphur in ZnS is given by:

32/97.4 x 100 = 33%

From the results obtained sulphur has the highest percentage by mass in sodium sulphide.

5 0
3 years ago
If we have 1.23 mol of NaOH in solution and 0.85 mol of Cl2 gas is available to react, which one is the limiting reactant? Give
Vinil7 [7]

Answer:

NaOH is the limiting reactant.

Explanation:

Hello there!

In this case, since the reaction taking place between sodium hydroxide and chlorine has is:

NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O

Which must be balanced according to the law of conservation of mass:

2NaOH+Cl_2\rightarrow NaCl+NaClO+H_2O

Whereas there is a 2:1 mole ratio of NaOH to Cl2, which means that the moles of the former that are consumed by 0.85 moles of the latter are:

n_{NaOH}=0.85molCl_2*\frac{2molNaOH}{1molCl_2}\\\\n_{ NaOH}=1.7molNaOH

Therefore, since we just have 1.23 moles out of 1.70 moles of NaOH, we infer this is the limiting reactant.

Regards!

3 0
3 years ago
Which of the following is evidence for sea floor
Basile [38]
What are the following options?
6 0
3 years ago
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