Answer:
c...............
Explanation:.............................yuuuuuuuuuuuuuuuuuuuuuwoopuuuuuuuu
Answer:
0.80m of KOH
Explanation:
Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.
In the problem, the solute is KOH and solvent is water.
Moles of 36g KOH -Molar mass: 56.1g/mol- are:
36g KOH × (1mol / 56.1g) = <em>0.642 moles of KOH</em>
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Now, as density of water is 1g/mL, mass of 800mL of water is:
800mL × (1g / mL) × (1kg / 1000g) = <em>0.800kg of water</em>
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Thus, molality is:
0.642moles of KOH / 0.800kg = <em>0.80m of KOH</em>
Answer:
sodium sulphide.
Explanation:
First, let us obtain the percentage of sulphur in both compounds. This is illustrated below:
For sodium sulphide(Na₂S):
Molar Mass of Na₂S = (23x2) + 32 = 46 + 32 = 78g/mol
Percentage of sulphur in Na₂S is given by:
32/78 x 100 = 41%
For zinc sulphide(ZnS):
Molar Mass of ZnS = 65.4 + 32 = 97.4g/mol
Percentage of sulphur in ZnS is given by:
32/97.4 x 100 = 33%
From the results obtained sulphur has the highest percentage by mass in sodium sulphide.
Answer:
NaOH is the limiting reactant.
Explanation:
Hello there!
In this case, since the reaction taking place between sodium hydroxide and chlorine has is:
Which must be balanced according to the law of conservation of mass:
Whereas there is a 2:1 mole ratio of NaOH to Cl2, which means that the moles of the former that are consumed by 0.85 moles of the latter are:
Therefore, since we just have 1.23 moles out of 1.70 moles of NaOH, we infer this is the limiting reactant.
Regards!
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