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Bad White [126]
2 years ago
12

Aaron, Blaine, and Cruz are solving the equation 4 7 (7 − n) = −1. Aaron started his solution by multiplying both sides of the e

quation by 7 4. Blaine started by using the distributive property to multiply 4 7 by both 7 and −n. Cruz started by dividing both sides of the equation by 4 7. Which of the following is true? Blaine and Cruz made an error in picking their first steps. Cruz made an error in picking his first step. All three made an error because the right side equals -1. All three chose a valid first step toward solving the equation.
Mathematics
2 answers:
likoan [24]2 years ago
5 0

Answer:

D.) All three chose a valid first step toward solving the equation.

Step-by-step explanation:

D is your answer

<u>Have a good day</u> :)

Nadya [2.5K]2 years ago
3 0

Answer:

D). All three choose a valid step toward solving the equation

Step-by-step explanation:

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Help! I don't get this, and if it is easy to you, this isn't my paper, it is my friends! &lt;3
mihalych1998 [28]

(1 + i)/(1 + 2i)

To simplify this, we need to multiply both sides by the conjugate.

(1 + i)(1 - 2i)

1 - 2i - i - 3i^2

Combine like terms.

3i^2 - 3i + 1

i^2 = -1

-3i - 2 is the simplified numerator.

(1 + 2i)(1 - 2i)

1 - 2i + 2i - 4i^2

1 - 4i^2

i^2 = -2

1 + 4

5


<h3><u>The simplified expression is ((-3i)/5) + ((-2)/5)</u></h3>
7 0
3 years ago
How would you write the following expression as a sum or difference? `"log"(root(3)(2 - x)/(3x))`
pashok25 [27]

<h3>log [ (√3)(2 - x)/(3x) ] = log (2 - x) - ¹/₂ log 3 - log x</h3>

<h3>Further explanation</h3>

Let's recall following formula about Exponents and Surds:

\boxed { \sqrt { x } = x ^ { \frac{1}{2} } }

\boxed { (a ^ b) ^ c = a ^ { b . c } }

\boxed {a ^ b \div a ^ c = a ^ { b - c } }

\boxed {\log a + \log b = \log (a \times b) }

\boxed {\log a - \log b = \log (a \div b) }

<em>Let us tackle the problem!</em>

\texttt{ }

\log \frac{\sqrt{3}(2-x)}{(3x)} = \log \sqrt{3} + \log (2-x) - \log (3x)

\log \frac{\sqrt{3}(2-x)}{(3x)} = \log 3^{1/2} + \log (2-x) - (\log 3 + \log x)

\log \frac{\sqrt{3}(2-x)}{(3x)} = \frac{1}{2} \log 3 + \log (2-x) - \log 3 - \log x

\log \frac{\sqrt{3}(2-x)}{(3x)} = \log (2-x) - \frac{1}{2}\log 3 - \log x

\texttt{ }

<h3>Learn more</h3>
  • Coefficient of A Square Root : brainly.com/question/11337634
  • The Order of Operations : brainly.com/question/10821615
  • Write 100,000 Using Exponents : brainly.com/question/2032116

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Exponents and Surds

Keywords: Power , Multiplication , Division , Exponent , Surd , Negative , Postive , Value , Equivalent , Perfect , Square , Factor.

7 0
3 years ago
Enter in the missing numbers to create equivalent ratios.
Westkost [7]

Answer specify

Step-by-step explanation:

Don’t know

4 0
3 years ago
The formula F=9/5(K−273.15)+32
Lyrx [107]
Just subtract 32, then divide by 9/5 (or multiply by the reciprical) then add 273.15.
K=5/9(F-32)+273.15
3 0
3 years ago
On a certain map. 2.5 inches represents 15 miles. Bay City and Greenwood are 4 inches apart on the map. What is the actual dista
lubasha [3.4K]
2.5 =15
4=x
4/2.5= 1.6
15 times 1.6 is 24
8 0
3 years ago
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