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2 years ago

Is NO2 an ionic or covalent bond? Will give brainliest for the correct answer

Chemistry

1 answer:

iragen [17]2 years ago

6 0

Answer:

Covalent

Explanation:

hi, How are you?

NO2 is already polar, due to the fact that nitrogen shares a maximum of 3 electrons. Thus N makes two covalent bonds with one oxygen, one covalent and one dative with the other. And there's still a free electron left that causes the molecule to bend, forming an angle, and so the NO2 molecule is polar with an angle other than 180.

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dexar [7]

Answer:Predatorrrrrrrrrrrrrrrr

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3 years ago

A 27 kg iron block initially at 375 C is quenched in an insulated tank that contains 130kg of water at 26 C. Assume the water th

Bess [88]

Solution :

a). Applying the energy balance,

$\Delta E_{sys}=E_{in}-E_{out}$

$0=\Delta U$

$0=(\Delta U)_{iron} + (\Delta U)_{water}$

$0=[mc(T_f-T_i)_{iron}] + [mc(T_f-T_i)_{water}]$

$0 = 27 \times 0.45 \times (T_f - 375) + 130 \times 4.18 \times (T_f-26)$

$t_f=33.63^\circ C$

b). The entropy change of iron.

$\Delta s_{iron} = mc \ln\left(\frac{T_f}{T_i} \right)$

$= 27 \times 0.45\ \ln\left(\frac{33.63 + 273}{375 + 273} \right)$

= -9.09 kJ-K

Entropy change of water :

$\Delta s_{water} = mc \ \ln\left(\frac{T_f}{T_i} \right)$

$= 130 \times 4.18\ \ln\left(\frac{33.63 + 273}{26 + 273} \right)$

= 10.76 kJ-K

So, the total entropy change during the process is :

$\Delta s_{tot} = \Delta s_{iron} + \Delta s_{water}$

= -9.09 + 10.76

= 1.67 kJ-K

c). Exergy of the combined system at initial state,

$X=(U-U_{0}) - T_0(S-S_0)+P_0(V-V_0)$

$X=mc (T-T_0) - T_0 \ mc \ \ln \left(\frac{T}{T_0} \right)+0$

$X=mc\left((T-T_0)-T_0 \ ln \left(\frac{T}{T_0} \right)\right)$

$X_{iron, i} = 27 \times 0.45\left(((375+273)-(12+273))-(12+273) \ln \frac{375+273}{12+273}\right)$

$X_{iron, i} =63.94 \ kJ$

$X_{water, i} = 130 \times 4.18\left(((26+273)-(12+273))-(12+273) \ln \frac{26+273}{12+273}\right)$

$X_{water, i} =-13.22 \ kJ$

Therefore, energy of the combined system at the initial state is

$X_{initial}=X_{iron,i} +X_{water, i}$

= 63.94 -13.22

= 50.72 kJ

Similarly, Exergy of the combined system at initial state,

$X=(U_f-U_{0}) - T_0(S_f-S_0)+P_0(V_f-V_0)$

$X=mc\left((T_f-T_0)-T_0 \ ln \left(\frac{T_f}{T_0} \right)\right)$

$X_{iron, f} = 27 \times 0.45\left(((33.63+273)-(12+273))-(12+273) \ln \frac{33.63+273}{12+273}\right)$

$X_{iron, f} = 216.39 \ kJ$

$X_{water, f} = 130 \times 4.18\left(((33.63+273)-(12+273))-(12+273) \ln \frac{33.63+273}{12+273}\right)$

$X_{water, f} =-9677.95\ kJ$

Thus, energy or the combined system at the final state is :

$X_{final}=X_{iron,f} +X_{water, f$

= 216.39 - 9677.95

= -9461.56 kJ

d). The wasted work

$X_{in} - X_{out}-X_{destroyed} = \Delta X_{sys}$

$0-X_{destroyed} =$

$X_{destroyed} = X_{initial} - X_{final}$

= 50.72 + 9461.56

= 9512.22 kJ

6 0

3 years ago

Please help !!!

stiv31 [10]

Answer:

2KClO3 》》2KCl +3O2

C+ O2》》CO2

number of C moles

Required O2 moles (According to the mole ratio )

Relevant to the first equation, find the moles the KClO3, which is used to produce that amount of O2 moles

Now you can find the mass of KClO3

I mentioned the useful steps which can guide you to get the answer.

Explanation:

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3 years ago

The density of dry air measured at 25 Celsius is 1.19 times 10 to the negative 3 what is the volume of 50.0g of air

Oksana_A [137]

Answer:

4.2 x 10⁴ mL

Explanation:

Data Given:

Density (d) of air = 1.19 x 10⁻³g/mL

Mass of the air (m) = 50 g

Volume of the air (V) = ?

Solution:

Formula will be used

d = m/V

As we have to find volume so rearrange the above equation

V = m/d . . . . . . . . . . . (1)

Put values in above equation 1

V = 50 g / 1.19 x 10⁻³g/mL

V = 4.2 x 10⁴ mL

So,

volume of dry air = 4.2 x 10⁴ mL

4 0

3 years ago

What is the correct formula for Tin (IV) chromate nonahydrate?

Mashcka [7]

Answer:

Sn(CrO4)2 or Cr2O8Sn

Explanation:

6 0

3 years ago

Is NO2 an ionic or covalent bond? Will give brainliest for the correct answer​

Is NO2 an ionic or covalent bond? Will give brainliest for the correct answer