What is the scale factor?

What irrational number is between 4.12 and 4.13 A.)sqrt{19} B.)sqrt{23}

fenix001 [56]

Sort{17} which equals 4.123

3 0

2 years ago

Help plz I'm desperate

lutik1710 [3]

Anna:

1st month = 18 + $\frac{3}{4}$ = 18 $\frac{3}{4}$ inches

2nd month = 18 $\frac{3}{4}$ + $\frac{3}{4}$ = 19 $\frac{1}{2}$

3rd month = 19 $\frac{1}{2}$ + $\frac{3}{4}$ = 20 $\frac{1}{4}$

4th month = 20 $\frac{1}{4}$ + $\frac{3}{4}$ = 21

5th month = 21 + $\frac{3}{4}$ = 21 $\frac{3}{4}$

Grace:

Because Anna is $\frac{9}{4}$ inches shorter than Grace, we can start the count from the third month:

1st month = 20 $\frac{1}{4}$

2nd month = 21

3rd month = 21 $\frac{3}{4}$

4th month = 21 $\frac{3}{4}$ + $\frac{3}{4}$ = 22 $\frac{1}{2}$

5th month = 22 $\frac{1}{2}$ + $\frac{3}{4}$ = 23

7 0

3 years ago

What’s 2percent of 300

love history [14]

Answer:

6

Step-by-step explanation:

2%=0.02

0.02*300=6

7 0

3 years ago

Suppose after 2500 years an initial amount of 1000 grams of a radioactive substance has decayed to 75 grams. What is the half-li

krok68 [10]

Answer:

The correct answer is:

Between 600 and 700 years (B)

Step-by-step explanation:

At a constant decay rate, the half-life of a radioactive substance is the time taken for the substance to decay to half of its original mass. The formula for radioactive exponential decay is given by:

$A(t) = A_0 e^{(kt)}\\where:\\A(t) = Amount\ left\ at\ time\ (t) = 75\ grams\\A_0 = initial\ amount = 1000\ grams\\k = decay\ constant\\t = time\ of\ decay = 2500\ years$

First, let us calculate the decay constant (k)

$75 = 1000 e^{(k2500)}\\dividing\ both\ sides\ by\ 1000\\0.075 = e^{(2500k)}\\taking\ natural\ logarithm\ of\ both\ sides\\In 0.075 = In (e^{2500k})\\In 0.075 = 2500k\\k = \frac{In0.075}{2500}\\ k = \frac{-2.5903}{2500} \\k = - 0.001036$

Next, let us calculate the half-life as follows:

$\frac{1}{2} A_0 = A_0 e^{(-0.001036t)}\\Dividing\ both\ sides\ by\ A_0\\ \frac{1}{2} = e^{-0.001036t}\\taking\ natural\ logarithm\ of\ both\ sides\\In(0.5) = In (e^{-0.001036t})\\-0.6931 = -0.001036t\\t = \frac{-0.6931}{-0.001036} \\t = 669.02 years\\\therefore t\frac{1}{2} \approx 669\ years$

Therefore the half-life is between 600 and 700 years

5 0

3 years ago

The cost of riding in a cab is $3.00 plus $0.75 per mile. The equation that represents this relation is y = 0.75x +3, where x is

Gemiola [76]

Answer:

Yes, the relation is a function.

Step-by-step explanation:

Given:

The equation that represents the cost of riding a cab is given as:

$y=0.75x+3$

Where, 'x' is the number of miles traveled and 'y' is the the total cost of the trip.

The above equation represents a line as it is of the form $y=mx+b$ which represents a line with constant slope.

Now, in order to plot this equation, we need at least two points.

Now, let $x =0$ , then

$y=0.75(0)+3=3$ . So, (0, 3) is a point on the line.

Let $x =1$ , then

$y=0.75(1)+3=3.75$ . So, (1, 3.75) is a point on the line.

Plot these two points on a graph and draw a line passing through these two points.

Now, for a relation to be a function, it should pass the vertical line test.

According to vertical line test, vertical lines passing through the graph must cut the graph at only 1 point for the graph to represent a function.

Here, we observe that vertical lines passing through the line will intersect the line only at one point. So, it represent a function.

8 0

3 years ago

What is the scale factor?​

What is the scale factor?