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sweet-ann [11.9K]
2 years ago
11

Please answer this i would greatly apreciat this

Mathematics
1 answer:
Misha Larkins [42]2 years ago
4 0

Answer:

The answer is a love

Step-by-step explanation:

I've already took this quiz and my answer was a

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If the y-intercept is b= -9 and the slope is m= 1. What is the slope intercept form? How do I set it up?
Rina8888 [55]

Answer:

y=1x-9 That's the equation if you're trying to figure that out and the slope would be 1/1

6 0
3 years ago
May someone help me please, I'm having alot of trouble. im giving poitns
saveliy_v [14]

Answer:

24 with a remainder of 1

Step-by-step explanation

so first you have to bring down the 3 so it is next to the six, and then you divide 36 by 15 and that equals 2. So you right a 2 on top. Then you have to multiply 2 and 15 and that equals 30 so you put a 30 below the 36. After you subtract, it equals 6 then you bring down the 1. Now you divide 61 and 15. The answer is 4 so you put a 4 on top next to the 2. After that you multiply 15 by 4 and that equals 60. You subtract 60 from 61, and you are left with a remainder of 1

5 0
3 years ago
Read 2 more answers
Which fraction is bigger 1/3 or 2/6. Explain
NikAS [45]
They are equal.

2/6 = 1/3

1 * 2 = 2
        -------
3 * 2 = 6 

do you see it?
5 0
3 years ago
Consider the system of equations.
Harman [31]

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

The given system of equations:

x  +  2y  =  1............(1)

-3x - 2y  =  5..........(2)

This can be written in matrix form as shown:

\left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}1\\5\end{array}\right]

Find the determinant of \left[\begin{array}{ccc}1&2\\-3&-2\end{array}\right]

\triangle = 1(-2) - 2(-3)\\\triangle = -2+6\\\triangle  = 4

\triangle_x = \left[\begin{array}{ccc}1&2\\5&-2\end{array}\right]\\\triangle_x = 1(-2)-2(5)\\\triangle_x = -2-10\\\triangle_x =-12

\triangle_y = \left[\begin{array}{ccc}1&1\\-3&5\end{array}\right]\\\triangle_y = 1(5)-1(-3)\\\triangle_y = 5 + 3\\\triangle_y =8

x = \frac{\triangle_x}{\triangle} \\x = \frac{-12}{4} \\x = -3

y = \frac{\triangle_y}{\triangle} \\y = \frac{8}{4} \\y = 2

The solution to the system of equations x + 2y = 1  and -3x-2y = 5 is:

x  = -3,  y = 2

Learn more here: brainly.com/question/4428059

3 0
2 years ago
Need help on all 3 if u can
vovikov84 [41]

Answer: 1. 2262

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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