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Alona [7]
2 years ago
6

2HgO O2 + 2Hg

Chemistry
1 answer:
stepladder [879]2 years ago
7 0

Answer:

33.5 grams of oxygen will be produced

Explanation:

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A covalent bond between an oxygen atom and a hydrogen atom is best described as _____.
Igoryamba
The answer is most likely nonmetals. :)
7 0
3 years ago
Imagine that you have a 7.00 L gas tank and a 3.50 L gas tank. You need to fill one tank with oxygen and the other with acetylen
GaryK [48]

Answer:

We should fill the acetylene tank to a pressure of 100 atm

Explanation:

Step 1: Data given

Volume tank 1 = 7.00 L

Tank 1 is filled with oxygen and has a pressure of 125 atm

Volume tank 2 = 3.50 L

Step 2: The balanced equation

2 C2H2 + 5 O2 → 4 CO2 + 2 H2O

Step 3: Calculate the pressure of acetylene

p(oxygen) * V(Oxygen) = n(Oxygen) * R * T  

p(Acetylene) * V(Acetylene) = n(Acetylene) * R * T

We can assume both tanks are at the same temperature, so we can write this as followed:

p(Oxygen)* V(Oxygen) / p(Acetylene)*V(Acetylene) = n(Oxygen) / n(Acetylene)    

⇒with n(Oxygen) / n(Acetylene) = 5/2

⇒with p(Oxygen) = 125atm

⇒V(Oxygen) =7L

⇒V(Acetylene) = 3.5L

⇒ this gives us:   (125 * 7) / (P(Acetylene) * 3.5) = 5/2

p(Acetylene) = 100 atm

We should fill the acetylene tank to a pressure of 100 atm

7 0
4 years ago
The average atomic weight of oxygen (O) is 15.9994 amu. It has three naturally occurring isotopes, 16 O, 17 O and 18 O, and 0.03
olganol [36]

Answer:

Abundance 18O = 0.201%

Abundance 16O = 99.768%

Explanation:

The average atomic weight of oxygen is defined as:

Average = Abundance 16O * 15.995amu + Abundance 17O * 16.999amu + Abundance 18O * 17.999amu

As average is 15.9994 amu and abundance of O17 = 0.037% = 3.7x10⁻⁴ we can write:

15.9994amu = Abundance 16O * 15.995amu + 3.7x10⁻⁴* 16.999amu + Abundance 18O * 17.999amu

15.9931 = Abundance 16O * 15.995amu + Abundance 18O * 17.999amu <em>(1)</em>

<em></em>

The abundance of each isotope = 1:

1 = Abundance 16O + Abundance 17O + Abundance 18O

1 = Abundance 16O + 3.7x10⁻⁴ + Abundance 18O

0.99963 = Abundance 16O + Abundance 18O <em>(2)</em>

<em></em>

Replacing (2) in (1):

15.9931 = (0.99963 - Abundance 18O) * 15.995amu + Abundance 18O * 17.999amu

15.9931 = 15.9891 - 15.995Abundance 18O + 17.999Abundance 18O

15.9931 = 15.9891 - 15.995Abundance 18O + 17.999Abundance 18O

4.0182x10⁻³ = 2.004Abundance 18O

2.005x10⁻³ = Abundance 18O = 0.201%

Thus, abundance of 16O in percentage is:

Abundance 16O = 100 - 0.201% - 0.031%

<h3>Abundance 16O = 99.768%</h3>
8 0
3 years ago
Given the balanced equation representing a reaction: 2NaCl -&gt; 2Na + Cl2 A 1170. gram sample of NaCl completely reacts, produc
arlik [135]
<span>Given the stoichiometric equation above and the amount of NaCl needed to produce the products, we can determine the amount of products produced. A 1170 gram NaCl using stoich produces 460 grams Na. This means the reaction makes a 100% conversion after. So, the amount of Cl2 produced from stoich is 709.61 grams.</span>
5 0
3 years ago
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Answer:

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Explanation:

6 0
4 years ago
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