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3 years ago

13

(wrong answers) 1 + 1 I will give u brainlets, i d k what it is called hehe

2 answers:

lapo4ka [179]3 years ago

5 0

Answer:

If you want me to give you a WRONG answer, then -1.

Gelneren [198K]3 years ago

4 0

It is most definitely 22

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14. Timothy has a set of plastic squares. The table shows the relationship between A, the area of each

andre [41]

Answer:

a

Step-by-step explanation:

a

3 0

3 years ago

Complete the following sentence: Two events that are mutually exclusive... ...cannot be calculated ...sometimes occur at the sam

elena55 [62]

Answer:

never occur at the same time

Step-by-step explanation:

In Statistics, two events that are mutually exclusive never occur at the same time. For instance, in tossing a coin we can either land heads or tails but not both. The two events are said to be mutually exclusive.

6 0

3 years ago

How many tenths are there in four fifths?

sleet_krkn [62]

So to find how many tenths, or 1/10's, there are in four fifths, or 4/5, divide 4/5 by 1/10.

$\frac{4}{5} \div \frac{1}{10}$

Now, remember that <u>dividing by a number is equivalent to multiplying by its reciprocal</u>. To find the reciprocal, just flip the numerator and denominator around. In this case, 1/10 would become 10/1. Flip 1/10 to its reciprocal, change the sign to multiplication, and multiply numerators with numerators and denominators with denominators:

$\frac{4}{5}\times \frac{10}{1}=\frac{40}{5}=8$

<u>In short, there are 8 tenths in four fifths.</u>

5 0

3 years ago

Read 2 more answers

Suppose that E(θˆ1) = E(θˆ2) = θ, V(θˆ 1) = σ2 1 , and V(θˆ2) = σ2 2 . Consider the estimator θˆ 3 = aθˆ 1 + (1 − a)θˆ 2. a Show

katen-ka-za [31]

Answer:

Step-by-step explanation:

Given that:

$E( \hat \theta _1) = \theta \ \ \ \ E( \hat \theta _2) = \theta \ \ \ \ V( \hat \theta _1) = \sigma_1^2 \ \ \ \ V(\hat \theta_2) = \sigma_2^2$

If we are to consider the estimator $\hat \theta _3 = a \hat \theta_1 + (1-a) \hat \theta_2$

a. Then, for $\hat \theta_3$ to be an unbiased estimator ; Then:

$E ( \hat \theta_3) = E ( a \hat \theta_1+ (1-a) \hat \theta_2)$

$E ( \hat \theta_3) = aE ( \theta_1) + (1-a) E ( \hat \theta_2)$

$E ( \hat \theta_3) = a \theta + (1-a) \theta = \theta$

b) If $\hat \theta _1 \ \ and \ \ \hat \theta_2$ are independent

$V(\hat \theta _3) = V (a \hat \theta_1+ (1-a) \hat \theta_2)$

$V(\hat \theta _3) = a ^2 V ( \hat \theta_1) + (1-a)^2 V ( \hat \theta_2)$

Thus; in order to minimize the variance of $\hat \theta_3$ ; then constant a can be determined as :

$V( \hat \theta_3) = a^2 \sigma_1^2 + (1-a)^2 \sigma^2_2$

Using differentiation:

$\dfrac{d}{da}(V \ \hat \theta_3) = 0 \implies 2a \ \sigma_1^2 + 2(1-a)(-1) \sigma_2^2 = 0$

⇒

$a (\sigma_1^2 + \sigma_2^2) = \sigma^2_2$

$\hat a = \dfrac{\sigma^2_2}{\sigma^2_1+\sigma^2_2}$

This implies that

$\dfrac{d}{da}(V \ \hat \theta_3)|_{a = \hat a} = 2 \ \sigma_1^2 + 2 \ \sigma_2^2 > 0$

So, $V( \hat \theta_3)$ is minimum when $\hat a = \dfrac{\sigma_2^2}{\sigma_1^2+\sigma_2^2}$

As such; $a = \dfrac{1}{2}$ if $\sigma_1^2 \ \ = \ \ \sigma_2^2$

4 0

4 years ago

Someone help me pls and thank you!

34kurt

Answer:

The volume would increase.

Step-by-step explanation:

The substance could move freer than that of before.

6 0

3 years ago

Read 2 more answers