X
216
1000
Hope it helps:)
Answer:
90
Step-by-step explanation:
The sum of squares of the deviation from mean=sum(x-xbar)²=?
x
12
6
15
9
18
12
xbar=sumx/n
xbar=(12+6+15+9+18+12)/6=72/6=12
x x-xbar (x-xbar)²
12 12-12=0 0
6 6-12=-6 36
15 15-12=3 9
9 9-12=-3 9
18 18-12=6 36
12 12-12=0 0
sum(x-xbar)²=0+36+9+9+36+0=90
So, the sum of squares of the deviations from the mean is 90.
Not sure its A but use this http://www.mathpapa.com/algebra-calculator.html
First multiply (-5/6) and (1/6) to get
then you subtract that from (8/9) to get
final answer is
X^3 = 16
x^3 = 4^2
x = ∛4^2
x = 4^2/3
answer
B. 4^2/3
------------------
x^5 = 16
x^5 = 2^4
x = 2^4/5
answer
D. x = 2^4/5
