Complex roots occur as conjugates so the other root is 3 + 2i
so we have the factored form
(x - (3 - 2i)(x - (3 + 2i)
= (x - 3 + 2i)(x - 3 - 2i)
= x^2 -3x - 2ix - 3x + 9 + 6i + 2ix - 6i- 4i^2
= x^2 -6x + 9 + 4
= x^2 - 6x + 13 Answer
Answer:
False
Step-by-step explanation:
A rhombus is a quadrilateral with
1. all side length equal
2. opposite side parallel
3. opposite angles are congruent.
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If there are two rhombus with same side length ,
conditions so that they must be always congruent.
1. Side length must be equal
2. corresponding angles to equal sides must also be equal.
It is possible that the sides of two rhombus will be same
but their angles can differ and hence the two rhombus may or may not be congruent.
Thus,
Two rhombuses with the same side lengths are always congruent
given statement is false
0.28 + 0.43 = 0.71 i put it in a calculator
Answer:
2(x+5) = 2x+10
Step-by-step explanation:
I'm assuming you can use any possible combination of two equivalent numerical expressions for your question.
2(x+5) = 2x+10
2 times x is 2x. 2 times 5 is 10. So, you get 2x+10
Answer:
just need points
Step-by-step explanation: