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Anvisha [2.4K]
2 years ago
9

100 POINTS!!!

Mathematics
2 answers:
Kryger [21]2 years ago
4 0

Answer:

x=150

y=240

Step-by-step explanation:

*Use simultaneous equation solving

1.Label your equations

x+y=390......1

2x+4y=1260......2

*make one of the unknowns subject of formula, to form equation 2

x=390-y.....3

*sub.3 into 2

2(390-y)+4y=1260

780-2y+4y=1260

2y+780=1260

y=240

sub. y into 3

x=390-y

x=390-240

x=150

liberstina [14]2 years ago
3 0
You would double the x+y=390 so you have 2x + 2y = 780

you’d take those away to be left with
2y = 480
y = 240

you’d then substitute y into the equation

x + 240 = 390
x = 150


This is called a simultaneous equation
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Answer:

I is clear that, the linear equation 5x+12=5x-7 has no solution.

Step-by-step explanation:

<u>Checking the first option:</u>

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6x+4=6x+4

\mathrm{Subtract\:}4\mathrm{\:from\:both\:sides}

6x+4-4=6x+4-4

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\mathrm{Subtract\:}6x\mathrm{\:from\:both\:sides}

6x-6x=6x-6x

0=0

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

<u>Checking the 2nd option:</u>

5x+12=5x-7

\mathrm{Subtract\:}5x\mathrm{\:from\:both\:sides}

5x+12-5x=5x-7-5x

\mathrm{Simplify}

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\mathrm{The\:sides\:are\:not\:equal}

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<u>Checking the 3rd option:</u>

4x+7=3x+7

\mathrm{Subtract\:}7\mathrm{\:from\:both\:sides}

4x+7-7=3x+7-7

\mathrm{Simplify}

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\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}

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\mathrm{Simplify}

x=0

<u>Checking the 4th option:</u>

-3\left(2x-5\right)=15-6x

\mathrm{Subtract\:}15\mathrm{\:from\:both\:sides}

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\mathrm{Simplify}\

-6x=-6x

\mathrm{Add\:}6x\mathrm{\:to\:both\:sides}

-6x+6x=-6x+6x

\mathrm{Simplify}

\mathrm{Both\:sides\:are\:equal}

\mathrm{True\:for\:all}\:x

Result:

Therefore, from the above calculations it is clear that, the linear equation

5x+12=5x-7 has no solution.

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