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2 years ago

The ratio of rainy days to non rainy days was 2 to 3. How many of the 30 days in April were rainy?

2 answers:

4 0

(30/(2+3))2=12

So there were 12 rainy days in April.

check...

If there are 2:3, rainy to non-rainy there are 5 equal parts of magnitude: 30/5=6

So each part is equal to 6. So 6*2=12 rainy days and 6*3=18 non-rainy days.

viktelen [127]2 years ago

3 0

20 days were rainy.

2:3=x:30
2/3=x/30
x=20

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which letter would be the most meaningful variable for the problem situation the weight of a box increase by 5

Anastaziya [24]

I don’t know but it’s probably y

8 0

2 years ago

Let p be the plane in space that intersects the x-axis at −5, the y-axis at −2, and the z-axis at 5. Find a vector v¯¯¯ that is

Lana71 [14]

Let P be the plane that intersects

x-axis at point (-5,0,0);
y-axis at point (0,-2,0);
z-axis at point (0,0,5).

Write the equation of the plane P:

$\left|\begin{array}{ccc}x-(-5)&y-0&z-0\\0-(-5)&-2-0&0-0\\0-(-5)&0-0&5-0\end{array}\right|=0\Rightarrow \left|\begin{array}{ccc}x+5&y&z\\5&-2&0\\5&0&5\end{array}\right|=0.$

Then

$-10(x+5)+10z-25y=0,\\ \\2(x+5)-2z+5y=0,\\ \\2x+5y-2z=-10.$

The coefficients at variables x, y and z are the coordinates of perpendicular vector to the plane. Thus

$\vec{v}=(2,5,-2)\perp P.$

Answer: $\vec{v}=(2,5,-2).$

7 0

3 years ago

(05.06)A chocolate bar measures 40 mm wide, 80 mm long, and 5 and 1 over 2 mm high. Will’s Wrapping Company is making a wrapper

photoshop1234 [79]

Answer:

Will’s Wrapping Company needs 7,720 mm2 of paper to wrap the chocolate bar.

Step-by-step explanation:

we know that

The amount of paper needed to make the wrapper is equal to the surface area of the chocolate bar

The surface area of a rectangular prism (chocolate bar) is equal to

$SA=2B+PH$

where

B is the area of the base

P is the perimeter of the base

H is the height of he prism

In this problem we have

$L=80\ mm\\W=5\frac{1}{2}\ mm=5.5\ mm\\H=40\ mm$

Find the area of the base

$B=LW=(80)(5.5)=440\ mm^2$

Find the perimeter of the base

$P=2(L+W)=2(80+5.5)=171\ mm$

Find the surface area

$SA=2(440)+171(40)\\SA=7,720\ mm^2$

5 0

2 years ago

Every evening, two weather stations issue weather forecast for the next day. The weather forecasts are independent. On average,

EleoNora [17]

Answer:

The probability is 0.6923

Step-by-step explanation:

Let's call R the event that the next day rains, S the event that the next day has sunny weather, R2 the event that the station 2 predicts rain and S1 the event that station 1 predict sunny weather.

The probability that the next day has sunny weather given that station 1 predicts sunny weather for the next day and station 2 predicts rain is calculated as:

P(S/S1∩R2) = P(S∩S1∩R2)/P(S1∩R2)

Where P(S1∩R2) = P(R∩S1∩R2) + P(S∩S1∩R2)

So, the probability P(R∩S1∩R2) that the next day rains, Station 1 predicts sunny weather and Station 2 predicts Rain is calculate as:

P(R∩S1∩R2) = 0.5 * 0.1 * 0.8 = 0.04

Because 0.5 is the probability that the next day rains, 0.1 is the probability that station 1 predicts sunny weather given that it is going to rain and 0.8 is the probability that station 2 predicts rain given that it is going to rain.

At the same way, the probability P(S∩S1∩R2) that the next day has sunny weather, Station 1 predicts sunny weather and Station 2 predicts Rain is calculate as:

P(S∩S1∩R2) = 0.5 * 0.9 * 0.2 = 0.09

Then, the probability P(S1∩R2) that station 1 predicts sunny weather for the next day, whereas station 2 predicts rain is:

P(S1∩R2) = 0.04 + 0.09 = 0.13

Finally, P(S/S1∩R2) is:

P(S/S1∩R2) = 0.09/0.13 = 0.6923

6 0

2 years ago

15/60=3/4 are they equivalent

Dvinal [7]

15/60 simplified is 1/4

1/4 is not equal to 3/4

4 0

2 years ago