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3 years ago

Find the area of the triangle where C = 18.5°, a = 32.4 cm, b = 49.2 cm HEHE HELP

Mathematics

2 answers:

LuckyWell [14K]3 years ago

8 0

if you have a triangle and don't know where are the base and the high use this formula

area = 0.5 × side × side × sin the angle between the 2 sides

area = o.5 (32.4) (49.2) (sin 18.5)

= 797.04 × sin 18.5

=252.9

Soloha48 [4]3 years ago

7 0

Answer:

questions mistake look questions and apply the formula 1/2 B×H

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2 years ago

Please help. Thank you

love history [14]

Answer:

The length of side x is $x = \sqrt{6}$

Step-by-step explanation:

Pythagorean Theorem:

In a right triangle, with sides a and b, and hypothenuse h, we have that:

$a^2 + b^2 = h^2$

In this question:

The vertical line on the sides means that both are equal, that is, measuring x, so $a = b = x$ .

Hypothenuse is the square root of 12. So $h = \sqrt{12}$

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