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Rashid [163]
3 years ago
6

Find the area of the triangle where C = 18.5°, a = 32.4 cm, b = 49.2 cm HEHE HELP

Mathematics
2 answers:
LuckyWell [14K]3 years ago
8 0

if you have a triangle and don't know where are the base and the high use this formula

area = 0.5 × side  × side  × sin the angle between the 2 sides

area = o.5 (32.4) (49.2) (sin 18.5)

         = 797.04 × sin 18.5

          =252.9

Soloha48 [4]3 years ago
7 0

Answer:

questions mistake look questions and apply the formula 1/2 B×H

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<h3>Vector</h3>

a. Vector (v)

Vector (v)=v (cos Ф, sin Ф)

V=1 while the counterclockwise angle that is measured from positive x=Ф=π/4

Hence:

Vector=3(cos π/4, sinπ/4)

Vector=(3/√2, 3√2)

b. Vector w:

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Vector w=(0, -1/2, √3/2)

Therefore the vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis is: (3/√2, 3√2) and The vector ws: (0, -1/2, √3/2).

The complete question is:

Resolve the following vectors into components:

a. The vector v in 2-space of length 3 pointing up at an angle of π/4 measured from the positive x-axis.

(b) The vector w in 3-space of length 1 lying in the yz-plane pointing upward at an angle of 2π/3 measured from the positive y-axis.

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