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2 years ago

Select the correct answer from each drag-drop menu.

Mathematics

1 answer:

Alekssandra [29.7K]2 years ago

3 0

Answer:

I think the answers bc, ab, and ac

Step-by-step explanation:

Sorry if it ends up being wrong i had the question before but im pretty sure that's the answer.

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6 5/8 - 2 3/8 in simplest form

777dan777 [17]

Would it be 4 1/4 ? Idk.. Hope this helps !

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4 years ago

Read 2 more answers

Martha made 3 birthday cards and she wants to make more. if she makes 5 cards an hour, How many cards will she have after 6 hour

frozen [14]

Well, since she makes 5 cards in ONE hour, we'll just multiply 5 times 6 to find out the total amount of cards made in 6 hours, which is 30. HOWEVER, we mustn't forget to add the amount of cards BEFORE she began making 5 cards per hour, which is 3, so 30 + 3 = 33. She made 33 cards after 6 hours. c:

8 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

What integer is 12 times -5?

seraphim [82]

Answer:

The integer is -60

Step-by-step explanation:

Is means equals and times means multiply

W = 12* (-5)

W = -60

6 0

3 years ago

-x^2 +9x-12 in vertex form<br> please help !!!

lesya [120]

Answer:

see explanation

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

To obtain this firm use the method of completing the square

Factor out - 1 from each term

y = - (x² - 9x + 12) $\frac{33}{4}$

To complete the square

add/subtract (half the coefficient of the x- term )² to x² - 9x

y = - (x² + 2( - $\frac{9}{2}$ )x + $\frac{81}{4}$ - $\frac{81}{4}$ + 12 )

= - ( (x - $\frac{9}{2}$ )² - $\frac{33}{4}$ )

y = - (x - $\frac{9}{2}$ )² + $\frac{33}{4}$ ← in vertex form

7 0

4 years ago