Question

Please any math experts help thanks you

Answer 1

Answer:

$\frac{p^2-25}{p^2-10p+25}$

We can factorise the numerator with the difference of squares formula:$x^2-y^2=(x+y)(x-y)$

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$\frac{p^2-5^2}{p^2-10p+25} =\frac{(p+5)(p-5)}{p^2-10p+25}$

Now we can factorise the denominator:

$\frac{(p+5)(p-5)}{p^2-10p+25} =\frac{(p+5)(p-5)}{(p-5)^2}$

$\frac{(p+5)(p-5)}{(p-5)^2} =\frac{(p+5)(p-5)}{(p-5)(p-5)}$

Cancel out the common factor of (p-5):

$\frac{(p+5)(p-5)}{(p-5)(p-5)} =\frac{(p+5)}{(p-5)}$