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4vir4ik [10]
3 years ago
10

Can anyone help me find the missing coefficient? 2n + (7n + 8) = n + 8

Mathematics
2 answers:
Ber [7]3 years ago
5 0

Answer:

n = 0

Step-by-step explanation:

2n + (7n + 8) = n + 8

2n + 7n + 8 = n + 8

9n + 8 = n + 8

9n -n = 8 - 8

8n = 0

n = 0

mars1129 [50]3 years ago
4 0

Answer:

Step-by-step explanation:

2n + 7n + 8 = n + 8

9n + 8 = n + 8

9n = n

n = 0

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3) A local school district has 4512 students this year. The student population is declining by 2.5% per year. How many students
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Answer:

Number of students(n1)= 4,402

Step-by-step explanation:

Giving the following information:

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3 years ago
A. Use composition to prove whether or not the functions are inverses of each other. B. Express the domain of the compositions u
Kryger [21]

Given: f(x) = \frac{1}{x-2}

           g(x) = \frac{2x+1}{x}

A.)Consider

f(g(x))= f(\frac{2x+1}{x} )

f(\frac{2x+1}{x} )=\frac{1}{(\frac{2x+1}{x})-2}

f(\frac{2x+1}{x} )=\frac{1}{\frac{2x+1-2x}{x}}

f(\frac{2x+1}{x} )=\frac{x}{1}

f(\frac{2x+1}{x} )=1

Also,

g(f(x))= g(\frac{1}{x-2} )

g(\frac{1}{x-2} )= \frac{2(\frac{1}{x-2}) +1 }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{\frac{2+x-2}{x-2} }{\frac{1}{x-2}}

g(\frac{1}{x-2} )= \frac{x }{1}

g(\frac{1}{x-2} )= x


Since, f(g(x))=g(f(x))=x

Therefore, both functions are inverses of each other.


B.

For the Composition function f(g(x)) = f(\frac{2x+1}{x} )=x

Since, the function f(g(x)) is not defined for x=0.

Therefore, the domain is (-\infty,0)\cup(0,\infty)


For the Composition function g(f(x)) =g(\frac{1}{x-2} )=x

Since, the function g(f(x)) is not defined for x=2.

Therefore, the domain is (-\infty,2)\cup(2,\infty)



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