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4 years ago

What is the equation of the line that passes through the point (-2,0) and has a slope of 5/2?

Mathematics

1 answer:

liq [111]4 years ago

7 0

Answer:

Step-by-step explanation:

y - 0 = 5/2(x + 2)

y = 5/2x + 5

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Find the distance between points P(8, 2) and Q(3, 8) to the nearest tenth.

riadik2000 [5.3K]

First of all to calculate the distance between two points we can use distance formula

d=Square Root [(x2-x1)^2 + (y2-y1)^2]

Now substitute the given points p(x1,y1) and q(x2,y2)in above distance formula

The values are X2=3, X1=8and Y2=8and Y1=2.

After Substituting the values

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d=Square Root(25+36]

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7 0

4 years ago

Plz help me out with this

nadya68 [22]

Given,

HK is the perpendicular bisector of GJ. So, GK = KJ.
GK = 2x + 10
KJ = 3x - 15

_______________

Find KJ .

_______________

First find the value of x

$\sf \: GK \: = KJ \\\sf 2x + 10 = 3x - 15 \\\sf 2x - 3x = - 15 - 10 \\ \sf - x = - 25 \\ \sf \: - > \boxed{\bf \: x = 25}$

Now, find the value of KJ.

$\sf3x - 15 \\ \sf= 3(25) - 15 \\ \sf=7 5 - 15 \\ = \boxed{\bf \: 60}$

-> The value of KJ is 60.

_______________

Hope it helps.

RainbowSalt2222

6 0

3 years ago

Read 2 more answers