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never [62]
2 years ago
13

During Mendel's second set of experiments, he allowed the F1, offspring from the first experiments to self-pollinate. Which of t

he following best describes the results? O A. About 25% of the Fz offspring expressed a different version of the studied trait than the parents had. O B. All the F2 offspring expressed a different version of the studied trait than the parents had. O C. All the F2 offspring expressed the same version of the studied trait as the parents had. D. About 25% of the Fz offspring expressed the same version of the studied trait as the parents had.​
Biology
2 answers:
elena-14-01-66 [18.8K]2 years ago
4 0
The answer is B. I did this question yesterday.
myrzilka [38]2 years ago
4 0

Answer:

B

Explanation:

A P E X

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according to the law of conservation of matter, matter is never created or destroyed. Yet in a food pyramid the amount of biomas
oksian1 [2.3K]

Answer:

According to the law of conservation of matter, matter is never created or destroyed but it can change from one form to another. Most of the biomass in a food web gets converted at each trophic level and it no longer remains apart of the food web. Most of the biomass is released into the atmosphere in the form of heat and hence cannot be transferred to the other trophic level. Also, matter is used up by the organism itself and converted into different forms. Most of the matter might get accumulated in the soil when the organisms of a trophic level die.

8 0
3 years ago
The following F2 results occur from a dihybrid cross (AaBb x AaBb): purple: A_B_ 9/16 white: aaB_ 3/16 white: A_bb 3/16 white: a
e-lub [12.9K]

Answer:

b. 3 (whilte) : 1(purple)

Explanation:

The first dihybrid crossing is between AaBb x AaBb

Now, if the double heterozygous traits self crossed, we have the following gametes shown below for the F₂ crossing.

AaBb = (AB, Ab, aB, ab)

                    AB                     Ab                     aB                     ab

AB                AABB                AABb                AaBB                AaBb

Ab                AABb                AAbb                AaBb                Aabb

aB                AaBB                 AaBb                aaBB                aaBb

ab                AaBb                 Aabb                 aaBb                aabb

We were being told that the results are;

purple: A_B_ 9/16

white: aaB_ 3/16

white: A_bb 3/16

white: aabb 1/16

From above, we can see that the same is true;

For Purple color; we Have (AABB and AaBb) since A is dominant to a and B is dominant to b.

∴ From the above punnet square; we have 9 purple colors which are:

(AABB, AABb, AaBB, AaBb, AABb, AaBb, AaBB, AaBb, AaBb) = 9/16

white: aaB_ ( since B is dominant to b, it can be either BB or Bb)

= (aaBB, aaBb, aaBb) = 3/16

white: A_bb ( since A is dominant to a, it can be either AA or Aa)

= (AAbb, Aabb, Aabb) = 3/16

white: aabb i.e homozygous recessive = (aabb) = 1/16

Furthermore, the question goes further by saying:

If a double heterozygote (AaBb) is crossed with a fully recessive organism (aabb), what phenotypic ratio is expected in the offspring?

If AaBb self crossed, we have:  (AB, Ab, aB, ab)

If aabb self crossed, we have: (ab, ab, ab, ab)

                    AB                     Ab                     aB                     ab

ab                AaBb                Aabb                aaBb                 aabb

ab                AaBb                Aabb                aaBb                 aabb

ab                AaBb                 Aabb               aaBb                 aabb

ab                AaBb                 Aabb                aaBb                aabb

AaBb ( purple)

= 4/16

= 1/4

= 0.25

= 25%

Aabb (white)

= 4/16

= 1/4

= 0.25

= 25%

aaBb (white)

= 4/16

= 1/4

= 0.25

= 25%

aabb (white)

= 4/16

= 1/4

= 0.25

= 25%

Now the proportion of white to purple =  (25%+25%+25%): 25%

=  75%:25%

= 3(white):1(purple)

We can therefore conclude that the expected phenotypic ratio in the cross between a double heterozygote (AaBb) with a fully recessive organism (aabb) yeids;

3 (whilte) : 1(purple)

8 0
3 years ago
Which of the following is an observation about the bird pictured below
lianna [129]
There is no picture of the bird.
8 0
3 years ago
Passive transport is the net movement of substances down a concentration gradient that requires metabolic energy. Active transpo
Dafna1 [17]

Answer:

The statement is false.

Explanation:

Passive transport moves molecules from one side of the membrane to the other with the energy of the chemical gradient (or concentration gradient). Otherwise, active transport uses the hydrolyzation of ATP to gain energy in order to move molecules across the membrane without taking into account the gradient.

4 0
3 years ago
3. How would you describe pressure?
shtirl [24]

pressure would be described as the force that is on an object

6 0
3 years ago
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