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nasty-shy [4]
2 years ago
11

Develop a model (diagram) that shows how different amounts of gravitational potential energy (GPE) are stored in the earth-ball

system when the ball is raised to different heights on the ramp.
Physics
1 answer:
hoa [83]2 years ago
3 0

The gravitational potential energy of the ball can be modelled in

relation to the velocity attained by the ball rolling down the ramp.

A model of the GPE of the ball is as follows;

  • The height of ball is directly proportional to the square of the velocity the ball reaches while rolling down the ramp. h ∝ v²

<h3>Which is the method used to obtain the model for the GPE of the ball?</h3>

The gravitational potential energy, GPE, is given as follows;

GPE = m·g·Δh

Where;

m = The mass of the ball

g = The acceleration due to gravity

Δh = The change in elevation of the ball

The gravitational energy of the ball at the starting (lowest) part of the

ramp, where Δh = 0, is 0.

When a small amount of energy is applied to the ball by moving it with a

slow speed, the ball moves some distance up the ramp then stops.

When a higher amount of energy is applied to the ball, the ball moves to

a higher point on the ramp.

When energy is applied to the ball, the energy is converted into

gravitational potential energy such that the height the ball reaches,

indicates the amount of gravitational potential energy in the ball.

Based on the model, we have;

Kinetic energy K.E. applied = GPE gained

Which gives;

\dfrac{1}{2} \cdot m \cdot v^2 = \mathbf{m \cdot g  \cdot h}

v^2 = 2 \cdot g  \cdot h

  • h \propto v^2
  • <u>The height of the ball is directly proportional to the square of the velocity</u>

Learn more about gravitational potential energy here:

brainly.com/question/16116226

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Thiết bị trao đổi nhiệt ngược chiều, nhiệt độ chất lỏng nóng vào là 310°C, ra là 115°c. Nhiệt độ chất lỏng lạnh vào là 25°c và r
Vika [28.1K]

Answer: 129.5 m

Explanation:

310 + 115 + 25 + 68 = 518

518 / 4 = 129.5 m

i think. Sorry if this is wrong

:)

5 0
3 years ago
A 100 kg box is suspended from two ropes. The "left rope makes an angle of 20" degrees with the vertical, and the right rope mak
GarryVolchara [31]

Explanation:

It is given that,

Mass of the box, m = 100 kg          

Left rope makes an angle of 20 degrees with the vertical, and the right rope makes an angle of 40 degrees.  

From the attached figure, the x and y component of forces is given by :

T_{1x} =-T_1 cos (20)

T_{2x} = T_2 cos (40)

mg_x = 0

T_{1y} = T_1 sin (20)

T_{2y} = T_2 sin (40)

mg_y= -mg

Let R_x and R_y is the resultant in x and y direction.

R_x=-T_1 cos (20)+T_2 cos (40)+0

R_y=T_1 sin(20)+T_2 sin(40)-mg

As the system is balanced the net force acting on it is 0. So,

-T_1 cos (20)+T_2 cos (40)+0=0.............(1)

T_1 sin(20)+T_2 sin(40)-100\times 9.8=0..................(2)

On solving equation (1) and (2) we get:  

T_1=866.86\ N (tension on the left rope)

T_2=1063.36\ N (tension on the right rope)

So, the tension on the right rope is 1063.36 N. Hence, this is the required solution.                            

7 0
3 years ago
A 174 pound Jimmy Cheek is riding on a 54 ft diameter Ferris Wheel. The normal force on Jimmy Cheek is 146 pounds when Jimmy is
Veronika [31]

To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.

I will also attach a free body diagram that allows a better understanding of the problem.

For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore

F_c = W-N

m\omega^2r = W-N

Here,

m = Net mass

\omega= Angular velocity

r = Radius

W = Weight

N = Normal Force

m\omega^2r = 174-146

The net mass is equivalent to

F = mg \rightarrow m = \frac{F}{g}

Then,

m = \frac{174lb}{32.17ft/s^2}

Replacing we have then,

(\frac{174lb}{32.17ft/s^2})\omega^2 (54ft) =174lb-146lb

Solving to find the angular velocity we have,

\omega = 0.309rad/s

Therefore the angular velocity is 0.309rad/s

6 0
3 years ago
A physics professor demonstrates the Doppler effect by tying a 600 Hz sound generator to a 1.0-m-long rope and whirling it aroun
VARVARA [1.3K]

Answer:

(a) f= 622.79 Hz

(b) f= 578.82 Hz

Explanation:

Given Data

Frequency= 600 Hz

Distance=1.0 m

n=120 rpm

Temperature =20 degree

Before solve this problem we need to find The sound generator moves on a circular with tangential velocity

So

Speed of sound is given by

c = √(γ·R·T/M) ............in an ideal gas

where γ heat capacity ratio

R universal gas constant

T absolute temperature

M molar mass

The speed of sound at 20°C is

c = √(1.40 ×8.314472J/molK ×293.15K  / 0.0289645kg/mol)

c= 343.24m/s

The sound moves on a circular with tangential velocity

vt = ω·r.................where   ω=2·π·n

vt= 2·π·n·r

vt= 2·π · 120min⁻¹ · 1m

vt= 753.6 m/min  

convert m/min to m/sec

vt= 12.56 m/s

Part A

For maximum frequency is observed  

v = vt

f = f₀/(1 - vt/c )

f= 600Hz / (1 - (12.56m/s / 343.24m/s) )  

f= 622.789 Hz

Part B

For minimum frequency is observed

v = -vt

f = f₀/(1 + vt/c )

f= 600Hz / (1 + (12.56m/s / 343.24m/s) )

f= 578.82 Hz

3 0
3 years ago
The measure of the force of gravity on an object, expressed as mass of the object times acceleration due to gravity is called
gulaghasi [49]

The measure of the force of gravity on an object, expressed as mass of the object times acceleration due to gravity is called

weight

4 0
3 years ago
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