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nasty-shy [4]
2 years ago
11

Develop a model (diagram) that shows how different amounts of gravitational potential energy (GPE) are stored in the earth-ball

system when the ball is raised to different heights on the ramp.
Physics
1 answer:
hoa [83]2 years ago
3 0

The gravitational potential energy of the ball can be modelled in

relation to the velocity attained by the ball rolling down the ramp.

A model of the GPE of the ball is as follows;

  • The height of ball is directly proportional to the square of the velocity the ball reaches while rolling down the ramp. h ∝ v²

<h3>Which is the method used to obtain the model for the GPE of the ball?</h3>

The gravitational potential energy, GPE, is given as follows;

GPE = m·g·Δh

Where;

m = The mass of the ball

g = The acceleration due to gravity

Δh = The change in elevation of the ball

The gravitational energy of the ball at the starting (lowest) part of the

ramp, where Δh = 0, is 0.

When a small amount of energy is applied to the ball by moving it with a

slow speed, the ball moves some distance up the ramp then stops.

When a higher amount of energy is applied to the ball, the ball moves to

a higher point on the ramp.

When energy is applied to the ball, the energy is converted into

gravitational potential energy such that the height the ball reaches,

indicates the amount of gravitational potential energy in the ball.

Based on the model, we have;

Kinetic energy K.E. applied = GPE gained

Which gives;

\dfrac{1}{2} \cdot m \cdot v^2 = \mathbf{m \cdot g  \cdot h}

v^2 = 2 \cdot g  \cdot h

  • h \propto v^2
  • <u>The height of the ball is directly proportional to the square of the velocity</u>

Learn more about gravitational potential energy here:

brainly.com/question/16116226

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ki77a [65]

Answer:

f' =1064.1025 Hz

Explanation:

We know that from doppler's effect

f'=\frac{v+v_0}{v-v_s}f

f'= observed frequency

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v= velocity of sound waves = 332 m/s

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v_s= velocity of source. ( let velocity of car be 20 m/s)

therefore,

f'=\frac{332+0}{332-20}\times1000

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3 0
3 years ago
A vessel containing 200 ml hydrogen gas at pressure 500torr at temperature 10 degree C.Find its volume when pressure increased t
Margaret [11]

Answer:

When the pressure and the temperature are increased the volume is 285.7 ml.

Explanation:

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Initially, when V₁ = 200 ml, P₁ = 500 torr and T₁ = 10 °C, we have:

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By equating (1) with (2):

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}                

V_{2} = \frac{P_{1}V_{1}T_{2}}{T_{1}P_{2}} = \frac{500 torr*200 ml*20 ^{\circ} C}{10 ^{\circ} C*700 torr} = 285.7 ml

Therefore, when the pressure and the temperature are increased the volume is 285.7 ml.                                                

I hope it helps you!                  

3 0
3 years ago
newtons 3rd law of motion states that "every action has an equal and oppisite reaction" A golf ball was hit with a force of 200
jolli1 [7]
This relates to newtons law of motion because that golf ball hit so hard that it went the same speed. because its force the more u like hit it your gonna get that force.
hope this makes sense

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Answer:

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