All categories

2 years ago

A system consists of two charges,

Physics

1 answer:

svet-max [94.6K]2 years ago

6 0

Answer:

the force exerted on the charge 10 q have a magnitude that is greater than F

Explanation:

The relation between the force and the charge are direct proportionality, it implies that as the charges is increasing the forces will be increasing too

You might be interested in

Which of the following classifications of star temperature is coolest?

Oliga [24]

The hottest would be the O type and the coolest is M

3 0

3 years ago

Read 2 more answers

A man is traveling on a bicycle at 14 m/s along a straight road that runs parallel to some railroad tracks. He hears the whistle

deff fn [24]

Answer:

Explanation:

b ) The problem is based on Doppler's effect of sound

f = f₀ x (V - v₀) /( $V+v_s$ )

f is apparent frequency ,f₀ is real frequency , V is velocity of sound , v₀ is velocity of observer going away , $v_s$ is velocity of source going away

778 = 840 x (340 - 14)/ (340 + $v_s$ )

340 + $v_s$ = 341.18

$v_s$ = 1.18 m /s

it will go away from the observer or the cyclist.

speed of train = 1.18 m /s

a )

For a stationary observer v₀ = 0

f = f₀ x V /( $V+v_s$ )

= 840 x 340 / (340 + 1.180)

= 837 Hz

6 0

2 years ago

Compare convergent plate boundaries that have the same density to convergent plate boundaries with different densities.

andrey2020 [161]

Answer:

If the two plates are of equal density, they usually push up against each other, forming a mountain chain. If they are of unequal density, one plate usually sinks beneath the other in a subduction zone. Hope this helps!

Explanation:

4 0

3 years ago

A 0.300 kg ball, moving with a speed of 2.5 m/s, has a head-on collision with at 0.600 kg ball initially at rest. Assuming a per

FrozenT [24]

Answer:

1.25 m/s

Explanation:

Given,

Mass of first ball=0.3 kg

Its speed before collision=2.5 m/s

Its speed after collision=2 m/s

Mass of second ball=0.6 kg

Momentum of 1st ball=mass of the ball*velocity

=0.3kg*2.5m/s

=0.75 kg m/s

Momentum of 2nd ball=mass of the ball*velocity

=0.6 kg*velocity of 2nd ball

Since the first ball undergoes head on collision with the second ball,

momentum of first ball=momentum of second ball

0.75 kg m/s=0.6 kg*velocity of 2nd ball

Velocity of 2nd ball=0.75 kg m/s ÷ 0.6 kg

=1.25 m/s

4 0

2 years ago

The force of gravity on a 1 kg object on the Earth's surface is approximately 9.8 N. For the same object in low-earth orbit arou

mojhsa [17]

Answer:

g = 8.61 m/s²

Explanation:

distance of the International Space Station form earth is 200 Km

mass of the object = 1 Kg

acceleration due to gravity on earth = 9.8 m/s²

mass of earth = 5.972 x 10²⁴ Kg

acceleration due to gravity = ?

r = 6400 + 200 = 6800 Km = 6.8 x 10⁶ n

using formula

$g = \dfrac{GM}{r^2}$

$g = \dfrac{6.67\times 10^{-11}\times 5.972\times 10^24}{(6.8\times 10^6)^2}$

g = 8.61 m/s²

3 0

3 years ago