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3 years ago

What is the common ratio in this sequence: 3, 12, 48, 192? A. 1/4 B. -4 C. 3 D. 4

Mathematics

2 answers:

choli [55]3 years ago

7 0

The Correct Answer Is

C

frozen [14]3 years ago

4 0

I believe c is correct!!!!

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William works at a nearby electronics store. He makes a commission of 6% on everything he sells. If he sells a computer for$764.

Sedaia [141]

Commission=0.06×764=$45.84

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3 years ago

Last one, So so sorry!

zvonat [6]

C and D are the same, so its between A and B, which concludes your answer should be B

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3 years ago

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Help solve this I’m not sure if my answer was right. Pythagorean theorem.

Ganezh [65]

Answer:

C. since 8, 15, 17 are pythagorean triples

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3 years ago

Leanne jumped a distance of 3 feet 8 inches. Monica jumped a distance of 4 feet 6 inches. How many more inches did Monica jump t

mote1985 [20]

Answer:

10 more inches

Step-by-step explanation:

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2 years ago

What are the solutions to the equation

frosja888 [35]

Answer:

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

Step-by-step explanation:

You have the quadratic function $2x^2-x+1=0$ to find the solutions for this equation we are going to use Bhaskara's Formula.

For the quadratic functions $ax^2+bx+c=0$ with $a\neq 0$ the Bhaskara's Formula is:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}$

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}$

It usually has two solutions.

Then we have $2x^2-x+1=0$ where a=2, b=-1 and c=1. Applying the formula:

$x_1=\frac{-b+\sqrt{b^2-4.a.c} }{2.a}\\\\x_1=\frac{-(-1)+\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_1=\frac{1+\sqrt{1-8} }{4}\\\\x_1=\frac{1+\sqrt{-7} }{4}\\\\x_1=\frac{1+\sqrt{(-1).7} }{4}\\x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}$

Observation: $\sqrt{-1}=i$

$x_1=\frac{1+\sqrt{-1}.\sqrt{7}}{4}\\\\x_1=\frac{1+i.\sqrt{7}}{4}\\\\x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$

And,

$x_2=\frac{-b-\sqrt{b^2-4.a.c} }{2.a}\\\\x_2=\frac{-(-1)-\sqrt{(-1)^2-4.2.1} }{2.2}\\\\x_2=\frac{1-i.\sqrt{7} }{4}\\\\x_2=\frac{1}{4}-(\frac{\sqrt{7}}{4})i$

Then the correct answer is option C.

$x_1=\frac{1}{4}+(\frac{\sqrt{7}}{4})i$ and $x_2=\frac{1}{4}-(\frac{\sqrt{7} }{4})i$

3 0

2 years ago