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dlinn [17]
1 year ago
14

Jaleel wrote a book. He wants to print some copies for his friends and family. The printing company charges a one-time fee of $$

$200, plus $$$2 for each printed book.
Is the number of books he prints a function of total cost?
Mathematics
1 answer:
baherus [9]1 year ago
4 0

Yes

Set the total cost toy, the number of books is x.

So, y= 200+2x

so cost is a dunction of the number of books

Hope this helps you!!!!! :D

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Find the surface area of a square pyramid with base edges<br> of 5 cm and a slant height of 3 cm.
ch4aika [34]

Answer:

Surface area of square pyramid = 55cm^{2}

Step-by-step explanation:

Let, b is the base  edges and s is the slant height

According to given condition:

b = 5 cm

s = 3 cm

Find out:

Surface area of square pyramid = ?

Formula:

Surface area of square pyramid = b^{2} + 2bs

Solution:

Surface area of square pyramid = b^{2} + 2bs

Surface area of square pyramid = 5^{2} + 2(5)(3)

Surface area of square pyramid = (25+ 30 ) cm^{2}

Surface area of square pyramid = 55cm^{2}

3 0
3 years ago
X cubed = 64/27 A= ±8/3 B= 8/3 C= ±4/3 D= 4/3
Digiron [165]

Answer:

D

Step-by-step explanation:

x³ = 64/27

Take the cube root of both sides.

x = ∛(64/27)

Distribute the cube root to the numerator and denominator.

x = (∛64)/(∛27)

Take the cube root of the terms.

x = 4/3

5 0
3 years ago
If 45% of a number, n, is 225, what is 74% of n?<br><br> A. 185<br> B. 298<br> C. 370<br> D. 406
Stolb23 [73]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Please help??? Pleaseeeeeeess
bixtya [17]
Angles 4 and 5 are Alternate Interior Angles because they are on opposite sides of the traversal line and on the inside sides between the parallel lines.
4 0
2 years ago
A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by V = x2h
creativ13 [48]

It is given in the question that

A rectangular box has a square base with an edge length of x cm and a height of h cm. The volume of the box is given by

V = x^2h cm^3

And the edge length of the base is 12 cm, the edge length of the base is decreasing at a rate of 2 cm/min, the height of the box is 6 cm, and the height is increasing at a rate of 1 cm/min.

Here we differentiate V with respect to t, and we use product rule, that is

V = 2xh(dx/dt)+ x^2(dh/dt)

Substituting the given values , we will get

[tex]dV/dt = 2(12)(6)(-2)+ 12^2(1)[/tex]

dV/dt = -288+144 = -144cm^3/min

So at that moment, the volume is decreasing at the rate of

144 cm^3/min

4 0
2 years ago
Read 2 more answers
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