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2 years ago

Which of these systems would be best solved by using the elimination method? (Check all that apply)

Mathematics

1 answer:

liraira [26]2 years ago

8 0

Answer:

option 1 and 4

Step-by-step explanation:

The elimination method should be used when there are two variables with the same number in front of them but different signs.

In the first system, the first equation has -8y while the second one has 8y.

Both equations have an 8y with different signs therefore using the elimination method would be most logical.

In the fourth system, the first equation has a -4x while the second one has 4x.

Both equations have 4x with different signs therefore using the elimination method would be most logical

Reasons it can't be the other options :

In the second system, no variable has the same number before it so no variable can be eliminated unless you multiply the equations by a common multiple. The best method for this system would be graphing

In the third system y is defined by an expression therefore using the substitution method is the most logical approach.

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The new number, 550, is 200 more than the original number. What is the approximate percent change?

Volgvan

Answer:150

Step-by-step explanation: you see what makes 550 200 plus what 350 then it equal 550 then you see 200 plus what equals 350 150 so that is a 150%

3 0

2 years ago

Read 2 more answers

Charla wants to determine the vertex of the function f(x) = x2 – 18x + 60 by changing the function into vertex form. Which state

7nadin3 [17]

Answer:

A. the x-coordinate of the vertex is greater than the y-coordinate.

Step-by-step explanation:

hope this helps

correct me if this is wrong

6 0

3 years ago

The price of commodity a is 4500 and increases at the rate of $6 every three months. Commodity b costs $5400 and increases at ra

ivanzaharov [21]

Let x be the months and y be the cost.

Rate of increase of commodity A = 6/3 = $2 per month
Equation:
y = 2x + 4500

Rate of increase of commodity B = 2/4 = $0.5 per month
Equation:
y = 0.5x + 5400

Equating the costs,
2x + 4500 = 0.5x + 5400
1.5x = 900
x = 600 months
x = 600 / 12 = 50 years

5 0

3 years ago

Prove that the two circles shown below are similar.

Setler [38]

Answer:

The scale factor is $\frac{R_{A}}{R_{C}}=\frac{5}{2}$

We can say that both circles are similar.

Step-by-step explanation:

If we move the little circle to the center of the bigger circle, so the translate vector will be (3,5).

Now we realize that the bigger circle is just a dilation of the smaller circle, the scale factor is:

$R_{A}=5$

$R_{C}=2$

$\frac{R_{A}}{R_{C}}=\frac{5}{2}$

Therefore, we can say that both circles are similiar.

I hope it helps you!

8 0

3 years ago

The cost of 3 markers and 2 pencils is $1.80. The cost of 4 markers and 6 pencils is $2.90. What is the cost of each item? Inclu

RideAnS [48]

Let M = marker cost
Let P = pencil cost

3 markers and 2 pencils cost 1.80 ==> 3M + 2P = 1.80

4 markers and 6 pencils cost 2.90 ==> 4M + 6P = 2.90

Multiply the first equation by (-3) and add it to the second equation

-9M - 6P = -5.40
4M + 6P = 2.90

-5M = -2.50
M = 0.50

Plug this value for M into the 1st equation and solve for P

3*(0.50) + 2P = 1.80
1.50 + 2P = 1.80
2P = 0.30
P = 0.15

So a marker costs 50 cents and a pencil costs 15 cents

7 0

2 years ago