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2 years ago

Which of these systems would be best solved by using the elimination method? (Check all that apply)

Mathematics

1 answer:

liraira [26]2 years ago

8 0

Answer:

option 1 and 4

Step-by-step explanation:

The elimination method should be used when there are two variables with the same number in front of them but different signs.

In the first system, the first equation has -8y while the second one has 8y.

Both equations have an 8y with different signs therefore using the elimination method would be most logical.

In the fourth system, the first equation has a -4x while the second one has 4x.

Both equations have 4x with different signs therefore using the elimination method would be most logical

Reasons it can't be the other options :

In the second system, no variable has the same number before it so no variable can be eliminated unless you multiply the equations by a common multiple. The best method for this system would be graphing

In the third system y is defined by an expression therefore using the substitution method is the most logical approach.

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Fill in the blanks for each box

Aliun [14]

Answer:

Step-by-step explanation:

7 0

3 years ago

$1.5 x 10^13 in decimal

inna [77]

The answer is 15,000,000,000,000

8 0

3 years ago

Test the series for convergence or divergence (using ratio test)

Triss [41]

Answer:

$\lim_{n \to \infty} U_n =0$

Given series is convergence by using Leibnitz's rule

Step-by-step explanation:

Step(i):-

Given series is an alternating series

∑ $(-1)^{n} \frac{n^{2} }{n^{3}+3 }$

Let $U_{n} = (-1)^{n} \frac{n^{2} }{n^{3}+3 }$

By using Leibnitz's rule

$U_{n} - U_{n-1} = \frac{n^{2} }{n^{3} +3} - \frac{(n-1)^{2} }{(n-1)^{3}+3 }$

$U_{n} - U_{n-1} = \frac{n^{2}(n-1)^{3} +3)-(n-1)^{2} (n^{3} +3) }{(n^{3} +3)(n-1)^{3} +3)}$

Uₙ-Uₙ₋₁ <0

Step(ii):-

$\lim_{n \to \infty} U_n = \lim_{n \to \infty}\frac{n^{2} }{n^{3}+3 }$

$= \lim_{n \to \infty}\frac{n^{2} }{n^{3}(1+\frac{3}{n^{3} } ) }$

= $= \lim_{n \to \infty}\frac{1 }{n(1+\frac{3}{n^{3} } ) }$

$=\frac{1}{infinite }$

$\lim_{n \to \infty} U_n =0$

∴ Given series is converges

3 0

3 years ago

Krispy Kritters Cereal used to come in a

shtirl [24]

Answer:

1335cm³

Step-by-step explanation:

The question above says that,Krispy kritters cereal used to come in a box with a volume of 2,850 cm3. However, the krispy kritters co. Designed a new larger box 22.5 cm wide, 6.2 cm deep, and 30 cm high and we are now asked to find "How many more cubic centimeters will the new box hold than the old box?

Now we are all aware that the volume of a cube or cuboid(since its a box ) is length multipled by width multiplied by the height.

And we were given the new dimensions which are;

12.5cm wide

6.2cm deep and

30cm high

Apply this given figures in the formula above and we have:

V = 12.5 × 6.2 × 30

= 4185cm³( this is the volume of the box)

Therefore,the difference in volume between the new box and the old box is

4185 - 2850 = 1335cm³

5 0

3 years ago

The question and information is on the photo pls if you can give me the work to.

alekssr [168]

Answer:

SI = 2052.61 ft

Step-by-step explanation:

cos 13 = 2000/SI

0.9744 = 2000/SI

multiply both sides by SI:

(SI)(0.9744) = 2000

divide both sides by 0.9744:

SI = 2052.61 ft

8 0

3 years ago