Answer:
X = T³KE⁴R / C²D⁵Y
Step-by-step explanation:
C²D⁵X / E⁴R = T³K / Y
=> C²D⁵XY = T³KE⁴R
=> X = T³KE⁴R / C²D⁵Y
A.AAS
B.
∠TSU=∠RQU
∠TUS=∠RUQ
TU=RU
105 maybe