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IRINA_888 [86]
2 years ago
13

#6 Larry works 15.5 days for a total of 131.75 hours. How many hours did he average per day?​

Mathematics
1 answer:
emmasim [6.3K]2 years ago
3 0

Answer:

Around 8.5 hours.

Step-by-step explanation:

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What is the midpoint of QR. Q(2,4) and R(-3,9)
Eduardwww [97]

Answer:

The answer is

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Step-by-step explanation:

The midpoint M of two endpoints of a line segment can be found by using the formula

M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

Q(2,4) and R(-3,9)

The midpoint is

M = ( \frac{2 - 3}{2}  \:  , \:  \frac{9 + 4}{2} ) \\

We have the final answer as

( -  \frac{1}{2}  \: , \:  \frac{13}{2})  \\

Hope this helps you

6 0
3 years ago
Lcm of 3x^(2) and 10
Ahat [919]

Answer:

the least common multiple is 18

Step-by-step explanation:

7 0
3 years ago
Solve x2 = 12x – 15 by completing the square. Which is the solution set of the equation? Solve x2 = 12x – 15 by completing the s
Svetlanka [38]

Answer: 6+\sqrt{21}\ \text{and}\ 6-\sqrt{21}

Step-by-step explanation:

Given

Quadratic equation is

x^2-12x+15=0

Solving by completing the square method

\Rightarrow x^2-2\cdot 6\cdot x+15=0\\\text{add and subtract 36}\\\Rightarrow x^2-2\cdot 6\cdot x+15+36-36=0\\\Rightarrow x^2-2\cdot 6\cdot x+36+(-36+15)=0\\\text{using}\ (a-b)^2=a^2+b^2-2ab\\\Rightarrow (x-6)^2-21=0\\\Rightarrow (x-6)^2=21\\\Rightarrow x-6=\pm \sqrt{21}\\\Rightarrow x=6\pm \sqrt{21}

The solution set of the equation is 6+\sqrt{21}\ \text{and}\ 6-\sqrt{21}

6 0
3 years ago
Read 2 more answers
The ratio of boys to girls in Ella’s grade is 3 to 4. The ratio of boys to girls in Minh’s grade is 4 to 5. Each grade has a tot
Aneli [31]

Answer:

In mih's school there are 100 boys

While in Ella's school there are 80 boys

Step-by-step explanation:

X*1/5=20

X=100

X*1/4=20

X=80

4 0
2 years ago
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
3 years ago
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