Answer:
<h3>On a coordinate plane, a cube root function goes through (negative 8, negative 2), has an inflection point at (0, 0), and goes thorugh (8, 2).</h3>
Step-by-step explanation:
![f(x)=\sqrt[3]{x}\\\\f(-8)=\sqrt[3]{-8}=-2\to(-8,\ -2)\\\\f(0)=\sqrt[3]{0}=0\to(0,\ 0)\\\\f(8)=\sqrt[3]{8}=2\to(8,\ 2)\\\\\\\sqrt[3]{a}=b\iff b^3=a\\\\\text{Therefore:}\\\\\sqrt[3]{-8}=-2\ \text{because}\ (-2)^3=-8\\\sqrt[3]0=0\ \text{because}\ 0^3=0\\\sqrt[3]{8}=2\ \text{because}\ 2^3=8](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D%5C%5C%5C%5Cf%28-8%29%3D%5Csqrt%5B3%5D%7B-8%7D%3D-2%5Cto%28-8%2C%5C%20-2%29%5C%5C%5C%5Cf%280%29%3D%5Csqrt%5B3%5D%7B0%7D%3D0%5Cto%280%2C%5C%200%29%5C%5C%5C%5Cf%288%29%3D%5Csqrt%5B3%5D%7B8%7D%3D2%5Cto%288%2C%5C%202%29%5C%5C%5C%5C%5C%5C%5Csqrt%5B3%5D%7Ba%7D%3Db%5Ciff%20b%5E3%3Da%5C%5C%5C%5C%5Ctext%7BTherefore%3A%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7B-8%7D%3D-2%5C%20%5Ctext%7Bbecause%7D%5C%20%28-2%29%5E3%3D-8%5C%5C%5Csqrt%5B3%5D0%3D0%5C%20%5Ctext%7Bbecause%7D%5C%200%5E3%3D0%5C%5C%5Csqrt%5B3%5D%7B8%7D%3D2%5C%20%5Ctext%7Bbecause%7D%5C%202%5E3%3D8)
C .... i hope I could help and that your staying safe .
Step-by-step explanation:
Hey there!
Given;
The points is; (-1 , 2) and slope is 4.
<em>Note:</em><em> </em><em>Use </em><em>one-point</em><em> formula</em><em>.</em>
<em>
</em>
<em>~</em><em> </em><em>Put </em><em>all</em><em> values</em><em>.</em>

~ Simplify it.


Therefore, the required equation is; 4x-y+6=0.
<h3>
<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em></h3>
Step-by-step explanation:
Clue: (I'm not giving the answer this is just clues) The word "absolute" helps you understand not to estimate so you want to get the RIGHT answer not the estimation.