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3 years ago

Please answer these thank u

Mathematics

1 answer:

balu736 [363]3 years ago

3 0

1. 3*3 + 3*8 = 9+24=33

2. 4*4+.5*2*4+5*5= 16+4+25=45

3. 5*10+4*10= 90

4. 24+.5*4*4 = 32

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Simplify: -0.8b+4.1c-(-3.2b)-0.1c

BigorU [14]

[ Answer ]

$\boxed{2.4b \ + \ 4c}$

[ Explanation ]

Simplify: -0.8b + 4.1c - (-3.2b) - 0.1c

-----------------------------------

Apply Rule: - (-a) = a

-0.8b + 4.1c + 3.2b - 0.1c

Group Like Terms

-0.8b + 3.2b + 4.1c - 0.1c

Add Similar Elements: -0.8b + 3.2b = 2.4b

2.4b + 4.1c - 0.1c

Add Similar Elements: 4.1c - 0.1c = 4c

2.4b + 4c

$\boxed{[ \ Eclipsed \ ]}$

8 0

3 years ago

Write an inequality that expresses the reason the lengths 5 feet, 10 feet, and 20 feet could not be used to make a triangle. Exp

Nadusha1986 [10]

Pythagoreon theorem
a^2+b^2=c^2
5^2+10^2=125 not 20^2

7 0

3 years ago

How do you find the missing area of the missing square

horrorfan [7]

Answer:

you will have to multiply by two

Step-by-step explanation:

5 0

3 years ago

How do you find how many times larger

masya89 [10]

Answer

whats the problem.

Step-by-step explanation:

4 0

3 years ago

If a coin is tossed three times, find probability of getting

Assoli18 [71]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

‣ A coin is tossed three times.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

${\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}$

$\star \: \tt P(E)= {\underline{\boxed{\sf{\red{ \dfrac{ Favourable \: outcomes }{Total \: outcomes} }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes $\tt [ \: n(s) \: ]$ = 8

1) Exactly 3 tails 

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: tails)} = \red{ \dfrac{1}{8}}$

2) At most 2 heads

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

$\therefore \sf Probability_{(at \: most \: 2 \: heads)} = \green{ \dfrac{7}{8}}$

3) At least 2 tails 

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

$\longrightarrow \sf Probability_{(at \: least \: 2 \: tails)} = \dfrac{4}{8}$

$\therefore \sf Probability_{(at \: least \: 2 \: tails)} = \orange{\dfrac{1}{2}}$

4) Exactly 2 heads 

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 2 \: heads)} = \pink{ \dfrac{3}{8}}$

5) Exactly 3 heads

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: heads)} = \purple{ \dfrac{1}{8}}$

$\rule{280pt}{2pt}$

8 0

2 years ago

Please answer these thank u​

Please answer these thank u