Answer:in a mass spectrum of BrCl four (4) peaks will be present
Explanation:
Cl and Br both have two naturally occuring isotopes.Br has 79Br which has abundance50.69% and 81Br which has abundance 49.31%.Similarly two isotopes of Cl are 35Cl having abundance 75.77% and 37Cl having abundance 24.23%.Chlorine and bromine combine and form bromine monochloride .Now they can combine with each other in four possible combinations wich are 1(81Br37Cl) 2(81Br35Cl) 3(79Br37Cl) 4(79Br35Cl) .So these four combined isotopes will show four peaks in mass spectrum.
Answer:
See the explanation
Explanation:
In this case, we have to remember that in the <u>monochlorination products</u> we only have to add one "Cl" with this in mind, we can have several options.
<u>a) 1-chloro-2,2-dimethylbutane</u>
<u>b) (R)-3-chloro-2,2-dimethylbutane</u>
<u>c) (S)-3-chloro-2,2-dimethylbutane</u>
<u>d) 1-chloro-3,3-dimethylbutane</u>
Additionally, from these 4 molecules, we will have 2 enantiomers. (R)-3-chloro-2,2-dimethylbutane and (S)-3-chloro-2,2-dimethylbutane.
See figure 1
I hope it helps!
Explanation:
Transition metals occupy the d block of the periodic table. Their location is right between the group 2A and 3A. Copper (Cu) is in the first row of the d-block elements. The image attached illustrates the position of the transition metals relative to other elements in the periodic table.
Answer:
A pure substance is a form of matter that has a constant composition and properties that are constant throughout the sample. Mixtures are physical combinations of two or more elements and/or compounds.
Answer:
1.20 M (3 s.f.)
Explanation:
In this question, we are trying to find the concentration of KCl after dilution. Note that the number of moles of KCl does not change.
Number of moles of KCl
= 44.7 ÷74.55
= 0.59960 mol (5 s.f.)
New volume
= 500 mL
= (500 ÷1000) L
= 0.5 L
Concentration after dilution
= 0.59960 ÷0.5
= 1.1992 mol/L
= 1.20 M (3 s.f.)
* M is the symbol for Molarity, which is also equal to mol/L