Question

Carbon reacts with oxygen to produce carbon dioxide (CO2 (g), Delta. Hf = –393. 5 kJ/mol) according to the equation below. Upper C (s) plus 2 upper O subscript 2 (g) right arrow upper C upper O subscript 2 (g). What is the enthalpy change of the reaction? Use Delta H r x n equals the sum of delta H f of all the products minus the sum of delta H f of all the reactants. –393. 5 kJ –196. 8 kJ 196. 8 kJ 393. 5 kJ.

Answer 1

The change in enthalpy for the reaction of carbon dioxide is -393.5 kJ/mol. Thus, option A is correct.

The change in enthalpy of the reaction is given by the energy of the product and the energy of reactant difference.

The chemical equation for the reaction is:

$\rm C \;(s)\;+\;2\;O_2\;(g)\;\to\;CO_2\;(g)$

Computation for the enthalpy change

The standard enthalpy change for carbon dioxide is -393.5 kJ/mol

The standard enthalpy change for oxygen is 0 kJ/mol

The change in enthalpy of reaction is given as:

$\rm \Delta \textit H=CO_2-2\;\times\;O_2\\\Delta \textit H=-393.5\;kJ/mol-2\;\times\;0\;kJ/mol\\\Delta \textit H=-393.5\;kJ/mol$

The change in enthalpy for the reaction of carbon dioxide is -393.5 kJ/mol. Thus, option A is correct.

Learn more about change in enthalpy, here:

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