A 180 counterclockwise rotation about the origin followed by a reflection of the y-axis
Area of square = 2^2 = 4
area of trapezoid = 1/2(4+7)(6) = 1/2(11)(6) = 33
area of figure = 33 - 4 = 29
answer
29 cm^2
Answer:
Total amount of fencing needed as an algebraic expression in terms of x is: <em>10x</em><em> </em><em>+</em><em> </em><em>3</em> .
Step-by-step explanation:
As it is given that each rectangle has the same dimensions, the dimensions of each rectangle must be: x units by 2x + 1 units.
Based on this, we can calculate the total amount of fencing needed.
Let width of each rectangle = x
Let length of each rectangle = 2x + 1
There are 4 widths and 3 lengths in total of fencing.
Therefore:
= 4 ( x ) + 3 ( 2x + 1 )
Expand:
= 4x + 6x + 3
Group like-terms:
= 10x + 3
Answer:
120
Step-by-step explanation:
Just add the 20 back to 40 and times by 2
40 + 20 = 60
60 * 2 = 120
28.35x 0.0625 = 1.772 (tax)
28.35 *0.2 = 5.67 (tip) 28.35+1.772+5.67 = ....
