<span>This is the equation made from the problem where x=mystery number </span><span>2x+3(x+1)=4(x-1)</span><span>
</span><span>Now let's solve for x! </span><span> </span><span>We start by distributing 3 into (X+1) </span><span> </span><span>3(x)=3x and 3(1)=3 </span><span> </span><span>Now our equation is 2x+3x+3=4(x-1) </span><span> </span><span>Let's combine both x values on the left side of the equation: 2x + 3x=5x </span><span> </span><span>We now have 5x+3=4(x-1) </span><span> </span><span>Let's distribute 4 into (x-1) </span><span> </span><span>4(x)=4x and 4(-1)=-4 </span><span> </span><span>Now our equation is 5x+3=4x-4 </span><span> </span><span>subtract 3 form both sides </span><span> </span><span>5x=4x-7 </span><span> </span><span>subtract 4x from both sides </span><span> </span><span>x=-7 </span><span> </span><span>Yay! So the number she is thinking of is -7!</span><span>
The null space of matrix is set of all solutions to matrix. The linearly independent vectors forms subset which are spanned and forms the null space. The null space of vector can be found by reducing its echelon. The non zero rows formed are the null spaces of matrix.
