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3 years ago

Which system of inequalities has no solution?

Mathematics

1 answer:

Luda [366]3 years ago

4 0

Answer:

i think c

Step-by-step explanation:

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F(x) = 4x*x is a function?

Roman55 [17]

Answer:

yes it is

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Write a function rule for your bacterium in the table where h is the number of hours, and b(h) is the bacterium at h hours.

djyliett [7]

Answer:

b(h) = 4^h

Step-by-step explanation:

The ratio of counts from one hour to the next is 4/1 = 16/4 = 64/16 ... = 4. The count at h=0 is 1, so that is the multiplier of the exponential term.

b(x) = 1×4^h

5 0

3 years ago

can someone explain scientific notation to me? i dont know if this would be a right question but i need it to be explained

Nikitich [7]

Answer:

In step by step explanation

Step-by-step explanation:

Move your decimal until you have one non-zero number left of your deciaml point the number of times you moved you decimal to the left will be the exponent you put attached to a ten.

8 0

3 years ago

If two rays share a common endpoint, then they will always form a line

Monica [59]

Unless they are opposite rays, then yes, they will always form a line.

4 0

3 years ago

Airline passengers arrive randomly and independently at the passenger-screening facility at a major international airport. The m

marshall27 [118]

Answer:

1. 0.0000454

2. 0.01034

3. 0.0821

4. 0.918

Step-by-step explanation:

Let X be the random variable denoting the number of passengers arriving in a minute. Since the mean arrival rate is given to be 10,

$X \sim Poi(\lambda = 10)$

1. Requires us to compute

$P(X = 0) = e^{-10} \frac{10^0}{0!} = 0.0000454$

2. We need to compute $P(X \leq 3) = P(X =0) + P(X =1) + P(X =2) + P(X =3)$

$P(X =1) = e^{-10} \frac{10^1}{1!} = 0.000454$

$P(X =2) = e^{-10} \frac{10^2}{2!} = 0.00227$

$P(X =3) = e^{-10} \frac{10^3}{3!} = 0.00757$

$P(X \leq 3) =0.0000454+ 0.000454 + 0.00227 + 0.00757 = 0.01034$

3. The expected no. of arrivals in a 15 second period is = $10 \times \frac{1}{4} = 2.5$ . So if Y be the random variable denoting number of passengers arriving in 15 seconds,

$Y \sim Poi(2.5)$

$P(Y=0) = e^{-2.5} \frac{2.5^0}{0!} = 0.0821$

4. Here we use the fact that Y can take values $0,1, \dotsc$ . So, the event that "Y is either 0 or $\geq$ 1" is a sure event ( i.e it has probability 1 ).

$P(Y=0) + P(Y \geq 1) = 1 \implies P(Y \geq 1) = 1 -P(Y=0) = 1 - 0.0821 = 0.918$

3 0

3 years ago