Answer:
Yes, Kreider has enough paint.
Step-by-step explanation:
We have been given Mr. Kreider wants to paint two doors and several shutters.
First of all, we will find the amount needed to paint 2 doors and several shutters as:
Convert mixed fraction into improper fraction:
Make a common denominator:
Combine numerators:
Amount of paint Mr. Kreider has:
Since amount needed for two doors and several shutters is 5.85 gallons and Mr. Kreider has 6 gallons of paint, therefore, Kreider has enough paint.
The correct answer would be 3(3+4)
This is because 3(7)=21 and
=9
Hope this helps! :)
The required system of inequalities is:
-2x + 3y > 15
y + 3x ≥ -4
y + 11x ≥ 6
In the given graph:
The dotted line represents the equation:
-2x + 3y = 15 → line 1.
The line towards the left of the shaded region represents the equation:
y + 3x = -4 → line 2.
The line towards the right of the shaded region represents the equation:
y + 11x = 6 → line 3.
Let's take a point in the shaded region and use the equations of the line to determine the inequality.
Consider the point (-2, 6) and substitute these values in the equations of all three lines.
Line 1:
LHS of line 1 = -2x + 3y = -2(-2) + 3(6) = 4 + 18 = 22
RHS of line 2 = 15.
Therefore, LHS > RHS.
⇒The required inequality is -2x + 3y > 15. It is a strict inequality since the equation of the line is not included in the shaded region.
Line 2:
LHS of line 2 = y + 3x = 6 +3(-2) = 6 - 6 = 0
RHS of line 2 = -4
Therefore, LHS > RHS.
⇒The required inequality is y + 3x ≥ -4. The "Equal to" symbol is used because the equation of the line is included in the shaded region.
Line 3:
LHS of line 3 = y + 11x = 6 + 11(-2) = 6 - 22 = -16
RHS of line 3 = 6
Therefore, LHS < RHS.
⇒The required inequality is y + 11x ≥ 6. The "Equal to" symbol is used because the equation of the line is included in the shaded region.
Therefore, the required system of inequalities is:
-2x + 3y > 15
y + 3x ≥ -4
y + 11x ≥ 6
Learn more at:
brainly.com/question/19491153
brainly.com/question/24299265
brainly.com/question/28038287
#SPJ9
Width of the rectangle =
Length of the rectangle =
Solution:
Area of the rectangle =
Width of the rectangle = greatest common factor of
Factor of =
Factor of =
Factor of =
Greatest common factor of
=
Width of the rectangle
Area of the rectangle = length × width
Divide by 5k² on both sides.
Cancel the common factor 5k², we get
Switch the sides.
Length =
Width of the rectangle =
Length of the rectangle =