Let y=x+6 be equation 1...
Replace equation 1 in equation 2
X+6 =-2x-3
X+2x = -3 -6
3x = -9
X = -3
Answer:
A) 0
Step-by-step explanation:
When x is divided by 11, we have a quotient of y and a remainder of 3
x/11 = y + 3
x = 11y + 3 ........(1)
When x is divided by 19, we have a remainder of 3 also
x/19 = p + 3 (p = quotient)
x = 19p + 3 ..........(2)
Equate (1) and (2)
x = 11y + 3 = 19p + 3
11y + 3 = 19p + 3
11y = 19p + 3 -3
11y = 19p
Divide both sides by 11
11y/11 = 19p/11
y = 19p/11
y and p are integers. 19 is a prime number. P/11 is also an integer
y = 19(integer)
This implies that y is a multiple of 19. When divided by 19, there is no remainder. The remainder is 0
Answer:
Step-by-step explanation:
When multiplying or dividing two negatives, multiply or divide the normal way and make your answer positive. Two negatives make a positive.
Inverse relationships are of the form xy=k or if you prefer y=k/x so to find the constant we can say:
18(0.25)=k=4.5
So you could say: IR=4.5 or I=4.5/R
