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Furkat [3]
2 years ago
10

Solve the system by substitution -5x+3y=2 y=2x

Mathematics
1 answer:
serious [3.7K]2 years ago
4 0

Answer:

(x,y)=(0,0)

Step-by-step explanation:

Simplify -5x+3y=2x

2y=2x

multiply both sides -7x+3y=0

-x+y=0

eliminiate one vaiable

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Find (f+g)(x) if f(x)=2/x+1 and g(x)=x-2
Semmy [17]
<span>(f+g)(x) if f(x)=2/x+1 and g(x)=x-2  

Add f and g together:     (f+g)(x) = (2/x) + 1 + x - 2 = (2/x) + x - 1</span>
4 0
3 years ago
Your water bill consists of five parts: A base hookup fee of $32.50, a water fee of $0.03 per gallon of water, a sewer fee of $0
Taya2010 [7]

hi

You have to keep calm and to treat data as it come.  

<u>1 ) Start by constant fees :  </u>

hook up fees  is  32.50  and  trash collection fees are 35

so contant fees  :  32.50 +35 =  67.50  

2 )  Now we have to deal with variable fees which depend on how much water is used

water fees :  

0.03 per gallon, and we have  4 000 gallon, so  :  

0.03*4 000 = 120  

Sewer fees  :  

0.01  per gallon, and we have  4 000 gallon, so  :  

0.01  * 4000 = 40  

3 ) Total before taxation we have :  

67.50 +120 +40 =  227.5  

4)  Now we apply tax on the total before tax.

tax is  5 % , which mean you rise the "off tax " price by 5 percent.  

<u>To grow a number of  X % ,  you multiply by  1+  X/ 100 </u>

here  X = 5  so  the multiplicator is  :  1 + 5/100 = 1.05  

<u>So total of the bill is :   227.5 * 1.05 = 238.875  </u>

The water compagny is  probably going to round it up to 238.88

4 0
1 year ago
Least common multiple of 168 and 76
yuradex [85]

Answer:

Best to draw out a factor tree.

4 0
2 years ago
Read 2 more answers
Convert 32505 into equivalent number with base 5​
velikii [3]

1s -0

5s- 1

25s- 0

125s- 0

625s- 2

3125s- 0

15625s- 2

2020010. I think this is right but would like so confirmation, just taught myself this!

6 0
3 years ago
A sample of radium has a weight of 1.5 mg and a half-life of approximately 6 years.
pogonyaev

Answer:

0.75 mg

Step-by-step explanation:

From the question given above the following data were obtained:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Amount remaining (N) =.?

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Half-life (t₁/₂) = 6 years

Time (t) = 6 years

Number of half-lives (n) =?

n = t / t₁/₂

n = 6/6

n = 1

Finally, we shall determine the amount of the sample remaining after 6 years (i.e 1 half-life) as follow:

Original amount (N₀) = 1.5 mg

Half-life (t₁/₂) = 6 years

Number of half-lives (n) = 1

Amount remaining (N) =.?

N = 1/2ⁿ × N₀

N = 1/2¹ × 1.5

N = 1/2 × 1.5

N = 0.5 × 1.5

N = 0.75 mg

Thus, 0.75 mg of the sample is remaining.

5 0
3 years ago
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