2.Each purse contains 8 coins. Find a rule to give the total number of coins.
1 answer:
<u>I</u><u>f</u><u> </u><u>w</u><u>e</u><u> </u><u>h</u><u>a</u><u>v</u><u>e</u><u> </u><u>t</u><u>o</u><u> </u><u>f</u><u>i</u><u>n</u><u>d</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>t</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>o</u><u>f</u><u> </u><u>c</u><u>o</u><u>i</u><u>n</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u>n</u><u> </u><u>w</u><u>e</u><u> </u><u>c</u><u>a</u><u>n</u><u> </u><u>u</u><u>s</u><u>e</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>f</u><u>o</u><u>l</u><u>l</u><u>o</u><u>w</u><u>i</u><u>n</u><u>g</u><u> </u><u>rule:</u>
- <u>I</u><u>f</u><u> </u><u>E</u><u>a</u><u>c</u><u>h</u><u> </u><u>P</u><u>u</u><u>r</u><u>s</u><u>e</u><u> </u><u>C</u><u>o</u><u>n</u><u>t</u><u>a</u><u>i</u><u>n</u><u>s</u><u> </u><u>8</u><u>c</u><u>o</u><u>i</u><u>n</u><u>s</u><u> </u><u>,</u><u>t</u><u>h</u><u>e</u><u>n</u><u> </u><u>w</u><u>e</u><u> </u><u>c</u><u>a</u><u>n</u><u> </u><u>f</u><u>i</u><u>n</u><u>d</u><u> </u><u>t</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>o</u><u>f</u><u> </u><u>c</u><u>o</u><u>i</u><u>n</u><u>s</u><u> </u><u>b</u><u>y</u><u> </u><u>m</u><u>u</u><u>l</u><u>t</u><u>i</u><u>p</u><u>l</u><u>y</u><u>i</u><u>n</u><u>g</u><u> </u><u>8</u><u> </u><u>t</u><u>o</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>p</u><u>u</u><u>r</u><u>s</u><u>e</u>
<u>T</u><u>h</u><u>u</u><u>s</u><u>,</u>
<h3><u>R</u><u>u</u><u>l</u><u>e</u><u> </u><u>i</u><u>s</u><u> </u><u>:</u></h3>
<u>︎⠀⠀ ⠀⠀ ⠀⠀ ⠀</u><u>︎⠀⠀ ⠀⠀ ⠀</u><u>8</u><u>×</u><u>T</u><u>o</u><u>t</u><u>a</u><u>l</u><u> </u><u>N</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>o</u><u>f</u><u> </u><u>P</u><u>u</u><u>r</u><u>s</u><u>e</u><u>.</u>
<h2><u>─━─━─━─━─━─━─━─━─━─━─━─━─</u></h2>
You might be interested in
if we take 64 to be the 100%, how much is 6¼% off of it?
![\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 64&100\\ x&6\frac{1}{4} \end{array}\implies \cfrac{64}{x}=\cfrac{100}{6\frac{1}{4}}\implies \cfrac{64}{x}=\cfrac{\frac{100}{1}}{\frac{25}{4}}\implies \cfrac{64}{x}=\cfrac{100}{1}\cdot \cfrac{4}{25} \\\\\\ \cfrac{64}{x}=16\implies 64=16x\implies \cfrac{64}{16}=x\implies 4=x \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{it had}}{64}-\stackrel{\textit{leakage}}{4}\implies \stackrel{\textit{remaining}}{60}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bccll%7D%20amount%26%5C%25%5C%5C%20%5Ccline%7B1-2%7D%2064%26100%5C%5C%20x%266%5Cfrac%7B1%7D%7B4%7D%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B64%7D%7Bx%7D%3D%5Ccfrac%7B100%7D%7B6%5Cfrac%7B1%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B64%7D%7Bx%7D%3D%5Ccfrac%7B%5Cfrac%7B100%7D%7B1%7D%7D%7B%5Cfrac%7B25%7D%7B4%7D%7D%5Cimplies%20%5Ccfrac%7B64%7D%7Bx%7D%3D%5Ccfrac%7B100%7D%7B1%7D%5Ccdot%20%5Ccfrac%7B4%7D%7B25%7D%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B64%7D%7Bx%7D%3D16%5Cimplies%2064%3D16x%5Cimplies%20%5Ccfrac%7B64%7D%7B16%7D%3Dx%5Cimplies%204%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Bit%20had%7D%7D%7B64%7D-%5Cstackrel%7B%5Ctextit%7Bleakage%7D%7D%7B4%7D%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bremaining%7D%7D%7B60%7D)
I think it is 36 well to what ik :)
answer:
the first one and the last one
good luck :)
hopefully, this helps
**please let me know if this was wrong**
have a great day !!
Domain = {x|x = 2, 9, 6}
Range = {y|y = c, 0}
I think this is the answer? I tried, it's better to fill it in than to leave it blank :/
Answer:
45 degrees
Step-by-step explanation:
Ok I think it is 45 degrees try that if not super sorry
