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Y_Kistochka [10]
2 years ago
13

How many wholes are in 11/3?

Mathematics
1 answer:
lesantik [10]2 years ago
5 0
There are 3 holes because if you do 4 thats to high cuz you would get 12 hope this is what you mean
You might be interested in
Hey:) can you please help me posted picture of question
trasher [3.6K]
Answer:
32x² + 36x + 9

Explanation:
To answer the question, we will simply multiply each term from the first bracket by each term from the second bracket and then combine like terms to get the final expression.

This can be done as follows:
(8x + 3)(4x + 3)
8x(4x) + 8x(3) + 3(4x) + 3(3)
32x² + 24x + 12x + 9
32x² + 36x + 9

Hope this helps :)
7 0
3 years ago
Read 2 more answers
Did I get this right plz be honest if i fail this i will fail this class
anyanavicka [17]

Step-by-step explanation:

Part A

A) The denominator is 665, so this is a terminating decimal.

B) 11/99 = 1/9 = 0.1111...

C) 256/999 = 0.256256256...

D) 25/909 = 275/9999 = 0.027502750275...

B has 1 repeating digit, C has 3 repeating digits, and D has 4 repeating digits.  So the correct answer is C.

Part B

A decimal that can be written as a ratio of integers is a rational number.

6 0
3 years ago
Suppose that each time Giannis Antetokounmpo shoots a free throw, he has a 3/4 probability of success. If Giannis shoots three f
GREYUIT [131]

Answer:

84.38% probability that he succeeds on at least two of them

Step-by-step explanation:

For each free throw, there are only two possible outcomes. Either Giannis makes it, or he does not. The free throws are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

He has a 3/4 probability of success.

This means that p = \frac{3}{4} = 0.75

Giannis shoots three free throws

This means that n = 3

What is the probability that he succeeds on at least two of them

P(X \geq 2) = P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.75)^{2}.(0.25)^{1} = 0.4219

P(X = 3) = C_{3,3}.(0.75)^{3}.(0.25)^{0} = 0.4219

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4219 + 0.4219 = 0.8438

84.38% probability that he succeeds on at least two of them

6 0
2 years ago
20. A rectangle has a length of x + 2 meters and a width of 2x - 5. (A.APR.1)
bija089 [108]

Answer:

A:

2(x + 2) + 2(2x - 5) =

2x + 4 + 4x - 10 =

6x - 6

perimeter = 6x - 6

B:

(x+2)(2x - 5)            expand the brackets:

2x² - 5x + 4x - 10

area = 2x² - x - 10

C:

area = 6x - 6 = (6 x 5) - 6 = 30 - 6 = 24

perimeter = 2x² - x - 10 = (2 x 5²) - 5 - 10 = (2 x 25) - 5 - 10 = 50 - 5 - 10 = 35

brainliest please? x

6 0
3 years ago
PLEASE PLEASE PLEASE PLEASE PLEASE HELP ME PLEASE HELP!?!?!!?!?!?!?!!?!!?!
Vladimir79 [104]
\text{Goal: Find } x \text{ such that:} \\ 2^x > 4x + 12

2^x > 4x + 12 \\ 2^x > 4(x + 3) \\ 2^{x - 2} > x + 3

\text{A lemma: } \\ \text{It is given that: } \\ 2^n > 2n + 1, \text{ } n > 3
\text{This can be proven by Mathematical Induction.}
\text{Using this lemma, we can manipulate the expression:} \\ 2^{x - 2} > 2(x - 2) + 1 = 2x - 3, \text{ } x > 5 \\ 2\cdot 2^{x - 2} > 2(2x - 3) \\ 2^{x - 1} > 4x - 12 \\ 2^{x - 1} + 24 > 4x + 12

\text{Observe the following: } 2^x \text{ will always grow faster than } 2^{x - 1} \\ \text{This implies that } 2^{x} > 2^{x - 1} + 24 > 4x + 12, \text{ given that } x > 5

\text{This means that the first month } f(x) > g(x) \text{ is Month 6.}
8 0
2 years ago
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