What is the result of multiplying the first equation by −3 and adding to the second equation?

Mrac [35]

Answer: 13 hours

Step-by-step explanation: I divided 60 by 5 to figure out how much she makes a hour and got 12 dollars an hour then I divided 156 by 12 and got the number of hours she worked which was 13

6 0

3 years ago

How to use the GCF and the distributive property of 40+ 50

iren2701 [21]

Hsndmf Nd didjsuduysysbsbsndndhyz

6 0

3 years ago

Helpp please!!!

zavuch27 [327]

Answer:

h, j2, f, g, j1, i, k, l (ell)

Step-by-step explanation:

The horizontal asymptote is the constant term of the quotient of the numerator and denominator functions. Generally, it it is the coefficient of the ratio of the highest-degree terms (when they have the same degree). It is zero if the denominator has a higher degree (as for function f(x)).

We note there are two functions named j(x). The one appearing second from the top of the list we'll call j1(x); the one third from the bottom we'll call j2(x).

The horizontal asymptotes are ...

h(x): 16x/(-4x) = -4
j1(x): 2x^2/x^2 = 2
i(x): 3x/x = 3
l(x): 15x/(2x) = 7.5
g(x): x^2/x^2 = 1
j2(x): 3x^2/-x^2 = -3
f(x): 0x^2/(12x^2) = 0
k(x): 5x^2/x^2 = 5

So, the ordering least-to-greatest is ...

h (-4), j2 (-3), f (0), g (1), j1 (2), i (3), k (5), l (7.5)

6 0

3 years ago

Vic is standing on the ground at a point directly south of the base of the CN Tower and can see the top when looking at an angle

Sindrei [870]

The angle of elevation of 61° and 72° with the height of the tower being 553.3 m. gives Vic's distance from Dan as approximately 356 meters.

<h3>How can the distance between Vic and Dan be calculated?</h3>

Location of Vic relative to the tower = South

Vic's sight angle of elevation to the top of the tower = 61°

Dan's location with respect to the tower = West

Dan's angle of elevation in order to see the top of the tower = 72°

Height of the tower = 553.3m

$tan( \theta) = \frac{opposite}{adjacent}$

$tan( 61 ^{ \circ}) = \frac{553.3}{ Vic' s\: distance \: to \: tower}$

$distance = \frac{553.3}{tan ( {61}^{ \circ} )} = 306.7$

Vic's distance from the tower ≈ 306.7 m

Similarly, we have;

$Dan's distance = \frac{553.3}{tan ( {72}^{ \circ} )} = 179.8$

Dan's distance from the tower ≈ 179.8 m

Given that Vic and Dan are at right angles relative to the tower (Vic is on the south of the tower while Dan is at the west), by Pythagorean theorem, the distance between Vic and Dan <em>d </em>is found as follows;