<h3><u>Question:</u></h3>
Ishaan is 2 times as old as Christopher. 35 years ago, Ishaan was 7 times as old as Christopher. How old is Christoper now?
<h3><u>Answer:</u></h3>
The present age of Christoper is 42 years old
<h3><u>Solution:</u></h3>
Given that Ishaan is 2 times as old as Christoper
Let the present age of Christoper be "x"
Then, Present age of Ishaan = 2 times as old as Christoper
present age of Ishaan = 2x
<em><u>35 years ago, Ishaan was 7 times as old as Christopher</u></em>
Age of Ishaan 35 years ago = Present age of Ishaan - 35
Age of Ishaan 35 years ago = 2x - 35
Similarly,
Age of christoper 35 years ago = Present age of christoper - 35
Age of christoper 35 years ago = x - 35
From given statement, 35 years ago, Ishaan was 7 times as old as Christopher
Age of Ishaan 35 years ago = 7 times the age of Christoper 35 years ago
(2x - 35) = 7(x - 35)
<em><u>Solve the above equation for "x"</u></em>
2x - 35 = 7x - 245
2x - 7x = -245 + 35
-5x = -210
<h3>x = 42</h3>
Thus present age of Christoper is 42 years old
We are given that the angle a is the right angle. So let
us work from this.
ab = 12 (the vertical side of the triangle)
bc = 13 (which if drawn can be clearly observed to be the
hypotenuse) = the side opposite to angle a
ca = 5 (the horizontal side of the triangle)
Since we are to find for the cosine ratio of angle c or
angle θ, therefore:
cos θ = adjacent side / hypotenuse
cos θ = ca / bc
cos θ = 5 / 13
Check out the attached image below for the illustration
of the triangle.
It shouldn't be too tough to find one of those, seeing that there are
an infinite number of them.
To create one, take any integer, positive or negative, and multiply it by itself.
Here are a few to put you in the mood:
1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, ...
784, 841, 900, 1024, 1225, 1600, 2500, 3600, 4900, 10000, 1 million, ...
Answer:
<h2>c. 2</h2>
Step-by-step explanation:
![4^\frac{1}{3}\cdot4^\frac{1}{6}\\\\\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=4^{\frac{1}{3}+\frac{1}{6}}=4^{\frac{1\cdot2}{3\cdot2}+\frac{1}{6}}=4^{\frac{2}{6}+\frac{1}{6}}=4^\frac{2+1}{6}=4^\frac{3}{6}=4^\frac{3:3}{6:3}=4^{\frac{1}{2}}\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\=\sqrt[2]{4^1}=\sqrt4=2](https://tex.z-dn.net/?f=4%5E%5Cfrac%7B1%7D%7B3%7D%5Ccdot4%5E%5Cfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5En%5Ccdot%20a%5Em%3Da%5E%7Bn%2Bm%7D%5C%5C%5C%5C%3D4%5E%7B%5Cfrac%7B1%7D%7B3%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%7B%5Cfrac%7B1%5Ccdot2%7D%7B3%5Ccdot2%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%7B%5Cfrac%7B2%7D%7B6%7D%2B%5Cfrac%7B1%7D%7B6%7D%7D%3D4%5E%5Cfrac%7B2%2B1%7D%7B6%7D%3D4%5E%5Cfrac%7B3%7D%7B6%7D%3D4%5E%5Cfrac%7B3%3A3%7D%7B6%3A3%7D%3D4%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%5C%5C%5C%5C%5Ctext%7Buse%7D%5C%20a%5E%5Cfrac%7Bm%7D%7Bn%7D%3D%5Csqrt%5Bn%5D%7Ba%5Em%7D%5C%5C%5C%5C%3D%5Csqrt%5B2%5D%7B4%5E1%7D%3D%5Csqrt4%3D2)
Answer:
8
Step-by-step explanation:
20 divided by 2.5 = 8 simple
