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NemiM [27]
2 years ago
7

I need help rlly bad I have no idea what’s the answer plsss help me!!! Which side is the long side?

Mathematics
1 answer:
mariarad [96]2 years ago
6 0

Answer:

I'm not very good with angles but I think the answer is AB

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We created this inequality to represent how Amy can meet her revenue goals:
brilliants [131]

Answer:

x = 2

Price = $29

Step-by-step explanation:

If x is the number of $2 dollars increases, then the minimum number of increases required to meet her goal is:

-100x^2 + 15,750x + 212,500 \geq 243,600\\-100x^2 + 15,750x -31,100\geq 0\\x^2 -157.5x + 311\geq 0\\x=\frac{157.5\pm\sqrt{157.5^2-(4*1*311)} }{2}\\ x_1= 2\\x_2=155.5

The only realistic value is x = 2 $2 increases

If the original price was $25, then the new rice required to reach Amy's goal is:

P=25+2*2\\P=\$29

The minimum ticket price is $29.

7 0
3 years ago
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3x < −2x + 7
Hunter-Best [27]
Answer: B

Because...
3x + 2x < -2x + 2x + 7
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8 0
3 years ago
Simplify sin θ / square root 1 - sin^2 θ
Soloha48 [4]

Recall that

\cos^2\theta+\sin^2\theta=1

which means

\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{\sqrt{\cos^2\theta}}

Now, \cos\theta could be positive or negative, which means \sqrt{\cos^2\theta}=|\cos\theta|. If we specifically knew the sign of \cos\theta was positive, then we can simplify and write

\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{\cos\theta}=\tan\theta

or if it's negative,

\dfrac{\sin\theta}{\sqrt{1-\sin^2\theta}}=\dfrac{\sin\theta}{-\cos\theta}=-\tan\theta

7 0
3 years ago
Hey guys ... just want to make this answer sure... subtract 2x²+3x+6 from 3x²+5x+7=? A)x²+2x+1 or
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Answer:

answer is A

Step-by-step explanation:

3 0
3 years ago
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4/3x - 4 = 5 + x <br> Can you help me?
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