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Yuri [45]
2 years ago
5

Answer this equation NEED HELP ASAP 30 POINTS

Mathematics
1 answer:
vivado [14]2 years ago
6 0

45456346456546546546

Step-by-step explanation:

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-1/100

Step-by-step explanation:

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Simplify!! Thank you :)
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Combine like terms.

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What is 3 in 3 - in 9 expressed as a single natural logarithm
xeze [42]

Answer:

ln(3)

Step-by-step explanation:

3 ln(3) = ln(3^3) = ln(27)

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3 years ago
Can you please help me with this
Veseljchak [2.6K]

Answer:

  D, E

Step-by-step explanation:

Each vector represents the horizontal and vertical translation amounts:

  \left[\begin{array}{c}\text{translation right}\\\text{translation up}\end{array}\right]

Translation left or down will result in negative values for the corresponding translation amounts.

__

We can consider only the lower-left corner to determine the amount of translation.

<h3>A ⇒ B</h3>

horizontal: 1 to -4, so -4-1 = -5 units

vertical: 2 to 0, so 0 -2 = -2 units

The translation vector is ...

  \left[\begin{array}{c}\text{-5}\\\text{-2}\end{array}\right]\qquad\text{matches choice D}

__

<h3>B ⇒ C</h3>

horizontal: -4 to -1, so -1 -(-4) = -1 +4 = 3 units

vertical: 0 to -4, so -4 -0 = -4 units

The translation vector is ...

  \left[\begin{array}{c}\text{3}\\\text{-4}\end{array}\right]\qquad\text{matches choice E}

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2 years ago
Prove that :
Viktor [21]

\text{L.H.S}\\\\=(\tan q + \sec q)^2\\\\\\=\left(\dfrac{\sin q}{ \cos q} + \dfrac 1{ \cos q} \right)^2\\\\\\=\left( \dfrac{1+ \sin q}{\cos q}\right)^2\\\\\\=\dfrac{(1+ \sin q)^2}{\cos^2 q}\\\\\\=\dfrac{(1+ \sin q)^2}{1-\sin^2 q}\\\\\\=\dfrac{(1 + \sin q)(1 + \sin q)}{(1+ \sin q)(1 - \sin q)}\\\\\\=\dfrac{1+ \sin q}{1- \sin q}\\\\=\text{R.H.S}\\\\\text{Proved.}

7 0
2 years ago
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