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2 years ago

3/5 pound of pasta feeds 6 people how many lbs does each person get

Mathematics

1 answer:

Zielflug [23.3K]2 years ago

5 0

Answer:

0.1 lbs or 1/10 lbs

Step-by-step explanation:

3/5 = 6/10 =

0.6 / 6 =

0.1

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Eric would like to buy a new math folder for $2.22 and a case of mechanical pencils for $2.95. He would also like to buy sticker

MrMuchimi

Answer:

0.5x+5.17: 10.00

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3 years ago

Read 2 more answers

16 increased by twice a number is -24 what is the solution?

Lynna [10]

Let x = the number.

"increased by" tells you we are adding.

"twice a number" tells you 2 times a number.

16 + 2x = - 24

Subtract 16 from both sides so that we have the variable on one sides and the constants on the other.

2x = - 24 - 16

2x = - 40

Divide by 2 to isolate the variable.

x = - 40/2 = - 20

Your solution is - 20.

To check your answer, plug in.

16 + 2(-20) = - 24

16 - 40 = - 24

- 24 = - 24

3 0

3 years ago

Find the least common denominator between the two fractions. and 2 12 6

SSSSS [86.1K]

The least common denominator is 2

5 0

3 years ago

Find the length of the arc

pickupchik [31]

Answer:

23.6 or 1 4 × π × 8 = 2 π if its not right let me know

Step-by-step explanation:

5 0

3 years ago

g A manufacturer is making cylindrical cans that hold 300 cm3. The dimensions of the can are not mandated, so to save manufactur

sdas [7]

Answer:

The dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

Step-by-step explanation:

A cylindrical can holds 300 cubic centimeters, and we want to find the dimensions that minimize the cost for materials: that is, the dimensions that minimize the surface area.

Recall that the volume for a cylinder is given by:

$\displaystyle V = \pi r^2h$

Substitute:

$\displaystyle (300) = \pi r^2 h$

Solve for <em>h: </em>

$\displaystyle \frac{300}{\pi r^2} = h$

Recall that the surface area of a cylinder is given by:

$\displaystyle A = 2\pi r^2 + 2\pi rh$

We want to minimize this equation. To do so, we can find its critical points, since extrema (minima and maxima) occur at critical points.

First, substitute for <em>h</em>.

$\displaystyle \begin{aligned} A &= 2\pi r^2 + 2\pi r\left(\frac{300}{\pi r^2}\right) \\ \\ &=2\pi r^2 + \frac{600}{ r} \end{aligned}$

Find its derivative:

$\displaystyle A' = 4\pi r - \frac{600}{r^2}$

Solve for its zero(s):

$\displaystyle \begin{aligned} (0) &= 4\pi r - \frac{600}{r^2} \\ \\ 4\pi r - \frac{600}{r^2} &= 0 \\ \\ 4\pi r^3 - 600 &= 0 \\ \\ \pi r^3 &= 150 \\ \\ r &= \sqrt[3]{\frac{150}{\pi}} \approx 3.628\text{ cm}\end{aligned}$

Hence, the radius that minimizes the surface area will be about 3.628 centimeters.

Then the height will be:

$\displaystyle \begin{aligned} h&= \frac{300}{\pi\left( \sqrt[3]{\dfrac{150}{\pi}}\right)^2} \\ \\ &= \frac{60}{\pi \sqrt[3]{\dfrac{180}{\pi^2}}}\approx 7.25 6\text{ cm} \end{aligned}$

In conclusion, the dimensions that minimize the cost of materials for the cylinders have radii of about 3.628 cm and heights of about 7.256 cm.

7 0

3 years ago