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schepotkina [342]
2 years ago
12

Samuel uses a uniform probability model for an experiment using a deck of 30 cards. There are 6 blue cards, 6 red cards, 6 green

cards, 6 yellow cards, and 6 brown cards in the deck. Cards will be drawn one at a time and then replaced in the deck before another card is drawn.
He uses the probability model to determine the probability of drawing a yellow card or a blue card.

What is P(yellow or blue)?

Enter your answer as a simplified fraction in the box [___]
Mathematics
2 answers:
STALIN [3.7K]2 years ago
6 0

DeeDee were were seeded seeded seeds

bogdanovich [222]2 years ago
5 0

Answer:

2/5

Step-by-step explanation:

i took the test

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A child who is 4 ½ feet tall casts a 6-foot shadow. At the same time, a nearby statue casts a 15-foot shadow. How tall is the st
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13 1/2 tall

Step-by-step explanation:

If 4 1/2 is the childs hight and their shadow is 6 feet, the shadow adds 2 1/2 to the height.

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Please help I’ll give brainliest
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4.05 as a mixed number
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4.05 in a mixed number is 4 1/2
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3 years ago
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Type the correct answer in each box. Use numerals instead of words. For this question, any answer that is not a whole number sho
egoroff_w [7]

Answer:

Step-by-step explanation:

Since we are not given the value of P, |Q|, R and S, we can as well assume values for them for the sake of this question.

Let P = 5, |Q| = 6, R =7 |S| = 2

Note that since Q and S are in modulus sign, they can return both positive and negative values.

P+Q = 5 + 6 (note that the positive value of Q is used since we need the greatest value of P+Q)

P+Q = 11

Hence the greatest value of P+Q is 11

For the least value of P+Q, we will use the negative value of Q as shown

P+Q = 5+(-6)

P+Q = 5-6

P+Q = -1

Hence the least value of P+Q is -1

Similarly:

R+S = 7 + 2 (note that the positive value of S is used since we need the greatest value of R+S)

R+S = 9

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For the least value of R+S, we will use the negative value of S as shown

R+S = 5+(-2)

R+S = 5-3

R+S = 2

Hence the least value of P+Q is 2

NOTE THAT THIS ARE ASSUMED VALUES. ALL YOU NEED IS TO PLUG IN THE VALUES OF P, Q and R THAT YOU HAVE IN CASE THE VALUES DIFFERS.

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3 years ago
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