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topjm [15]
2 years ago
13

What type of solvent would be required to dissolve nonpolar compounds?

Chemistry
2 answers:
mina [271]2 years ago
4 0
For example, ionic compounds, which are very polar, are often soluble in the polar solvent water. Nonpolar substances are likely to dissolve in nonpolar solvents. For example, nonpolar molecular substances are likely to dissolve in hexane, a common nonpolar solvent.
AnnZ [28]2 years ago
3 0

Answer:

Solvents composed of polar molecules, such as water, dissolve other polar molecules, such as table salt, while nonpolar solvents, such as gasoline, dissolve nonpolar substances such as wax.

Explanation:

In chemistry, a common rule for determining if a solvent will dissolve a given solute is "like dissolves like." Solvents composed of polar molecules, such as water, dissolve other polar molecules, such as table salt, while nonpolar solvents, such as gasoline, dissolve nonpolar substances such as wax.

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lisov135 [29]

Answer:

See explanation

Explanation:

a) The magnitude of intermolecular forces in compounds affects the boiling points of the compound. Neon has London dispersion forces as the only intermolecular forces operating in the substance while HF has dipole dipole interaction and strong hydrogen bonds operating in the molecule hence HF exhibits a much higher boiling point than Ne though they have similar molecular masses.

b) The boiling points of the halogen halides are much higher than that of the noble gases because the halogen halides have much higher molecular masses and stronger intermolecular forces between molecules compared to the noble gases.

Also, the change in boiling point of the hydrogen halides is much more marked(decreases rapidly)  due to decrease in the magnitude of hydrogen bonding from HF to HI. The boiling point of the noble gases increases rapidly down the group as the molecular mass of the gases increases.

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2 years ago
Which of the following is a unit of heat? 1. Fahrenheit 2. Energy 3. Joule 4. Celsius
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6 0
3 years ago
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For the following electrochemical reaction: Al3+(aq) + 3e -> Al(s) Eº = -1.66 V E° = 2.87 F2(g) + 2e -> 2F (aq) Calculate
makvit [3.9K]

<u>Answer:</u> The standard electrode potential of the cell is 4.53 V.

<u>Explanation:</u>

We are given:

E^o_{(F_2/F^-)}=2.87V\\E^o_{(Al^{3+}/Al)}=-1.66V

The substance having highest positive E^o potential will always get reduced and will undergo reduction reaction. Here, fluorine will undergo reduction reaction will get reduced.

Aluminium will undergo oxidation reaction and will get oxidized.

Substance getting oxidized always act as anode and the one getting reduced always act as cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

E^o_{cell}=2.87-(-1.66)=4.53V

Hence, the standard electrode potential of the cell is 4.53 V.

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