<span>If you look at the chlorine box, with the symbol Cl, you see the atomic mass is equal to 35.453 atomic mass units. This is the weighted average mass of chlorine, including its isotopes, as found in nature. This also means that one mole of chlorine atoms has a mass of 35.453 grams.</span>
Answer:
That means Cu2O is limiting reagent and C is excess reagent
Explanation:
Based on the reaction, 1 mole of Cu2O reacts per mole of C. The ratio of reaction is 1:1.
To solve this question we need to convert the mass of each reactant to moles. The reactant with the lower amount of moles is limiting reactant and the excess reactant is the reactant with the higher number of moles.
<em>Moles Cu2O -Molar mass: 143.09 g/mol-</em>
114.2g Cu2O * (1mol / 143.09g) = 0.798 moles Cu2O
<em>Moles C -Molar mass: 12.01g/mol-</em>
11.1g C * (1mol / 12.01g) = 0.924 moles C
<h3>That means Cu2O is limiting reagent and C is excess reagent</h3>
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<h3>
Answer:</h3>
7.226 × 10^23 molecules.
<h3>
Explanation:</h3>
- A compound is a substance that is made by two or more atoms from different elements.
- A mole of a compound contains a number of molecules equivalent to Avogadro's number, 6.022 × 10^23.
- That is, one mole of a compound contains 6.022 × 10^23 molecules.
In this case we are given;
Number of moles of H₂O as 1.2 moles
But, 1 mole of H₂O contains 6.022 × 10^23 molecules.
We are required to calculate the number of molecules present;
- To calculate the number of molecules we are going to multiply the number of molecules in one mole by the number of moles.
Number of molecules = 1.2 moles × 6.022 × 10^23 molecules/mole
= 7.226 × 10^23 molecules.
Thus, 1.2 moles of water contains 7.226 × 10^23 molecules.
Answer is: mass of silver chloride is 34,82 g.
Chemical
reaction: AgNO₃ +
NaCl → AgCl + NaNO₃.
<span>m(AgNO</span>₃) = 53,42 g..<span>
m(NaCl) = 14,19 g.
n(AgNO</span>₃) = m(AgNO₃) ÷ M(AgNO₃).<span>
n(AgNO</span>₃) = 53,42 g ÷ 169,87 g/mol.
n(AgNO₃) = 0,314 mol.
n(NaCl) = 14,19 g ÷ 58,4 g/mol.
n(NaCl) = 0,242 mol; limiting reactant.
From chemical reaction: n(NaCl) : n(AgCl) = 1 : 1.<span>
n</span>(AgCl)<span> = 0,242 mol.
m</span>(AgCl) = 0,252 mol · 143,32 g/mol.
m(AgCl) = 34,82 g.