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2 years ago

Which one is your favorite?

Chemistry

2 answers:

Rainbow [258]2 years ago

5 0

Answer:

My personal favorite is dragon ball super.

Explanation:

melamori03 [73]2 years ago

3 0

Answer:

all of them i seen all well almost all of dragon ball gt

Explanation:

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THIS IS DUE TODAY IF YOU HELP I WILL GIVE BRAINLIEST

sp2606 [1]

Answer:19. He says that he’s been really tired since several weeks ago. 20. A friend of us is going to pick us up at the airport. 21. I’ve worked like a waiter in the past, but I wouldn’t want to do it again. 22

Explanation:

7 0

2 years ago

Fe(s) + 2HCl(aq) --> FeCl2(aq) + H2(g)

soldier1979 [14.2K]

Answer:

In the option(A) moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

Explanation:

$Fe(s) + 2HCl(aq)\rightarrow FeCl_2(aq) + H_2(g)
$

Moles of HCl = n

Molarity of HCl = 1.0M

Volume of HCl solution = 30.0 mL = 0.030 L (1 mL = 0.001L)

$Moles=Molarity\times Volume (L)$

$n=1.0M\times 0.030 L=0.030 mol$

Moles of Fe = $\frac{0.56 g}{56 g/mol}=0.01 mol$

According to recation , 1mol of Fe reacts with 2 mol HCl. Then 0.01 mole of Fe will recat with :

$\frac{2}{1}\times 0.01 mol= 0.02 mol$ of HCl

This means that HCl uis in excess , hence excessive reagent.

Moles of HCl left unreacted :

= 0.030 mol - 0.020 mol = 0.010 mol

But in the option moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

8 0

3 years ago

What do elements in the same group in the periodic table have in common

Shalnov [3]

Answer:

The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons.

Explanation:

8 0

2 years ago

For the equilibrium

Mamont248 [21]

Answer:

Equilibrium concentrations of the gases are

$H_2S=0.596M$

$H_2=0.004 M$

$S_2=0.002 M$

Explanation:

We are given that for the equilibrium

$2H_2S\rightleftharpoons 2H_2(g)+S_2(g)$

$k_c=9.0\times 10^{-8}$

Temperature, $T=700^{\circ}C$

Initial concentration of

$H_2S=0.30M$

$H_2=0.30 M$

$S_2=0.150 M$

We have to find the equilibrium concentration of gases.

After certain time

2x number of moles of reactant reduced and form product

Concentration of

$H_2S=0.30+2x$

$H_2=0.30-2x$

$S_2=0.150-x$

At equilibrium

Equilibrium constant

$K_c=\frac{product}{Reactant}=\frac{[H_2]^2[S_2]}{[H_2S]^2}$

Substitute the values

$9\times 10^{-8}=\frac{(0.30-2x)^2(0.150-x)}{(0.30+2x)^2}$

By solving we get

$x\approx 0.148$

Now, equilibrium concentration of gases

$H_2S=0.30+2(0.148)=0.596M$

$H_2=0.30-2(0.148)=0.004 M$

$S_2=0.150-0.148=0.002 M$

3 0

2 years ago

Help brainliest plzzzz

konstantin123 [22]

The awnser is D or the 4th one

6 0

3 years ago

Read 2 more answers